Question

我试图像这样将新行保存到数据库

@SuppressWarnings("unchecked")
@Modifying 
public SMSIncoming save(@Param("smsIncoming") SMSIncoming smsIncoming);

在这里，我没有像下面那样设置ID：-

 SMSIncoming smsIncoming = new SMSIncoming();
 smsIncoming.setSender("6476963460");
 smsIncoming.setReceiver("6475603720");
 smsIncoming.setMsg("Testing Incoming messages");

 @Id
 @GeneratedValue
 private Long id;

在保存之前应自动生成

@SuppressWarnings("unchecked")
@Modifying  
public SMSIncoming save(@Param("smsIncoming") SMSIncoming smsIncoming);

JpaRepository<SMSIncoming, Long>

但是在这里我也遇到了很多异常，我尝试了所有无法通过的选项（AUTO，TABLE，SEQUENCE和IDENTITY），所以接下来我想从表中获取最大id并通过递增来保存。在这种方法中，我也面临着问题。

在使用IDENTITY关键字保存ID时发布问题跟踪：-

 `2019-03-26 11:32:15.347  INFO 5828 --- [           main] 
c.a.s.service.SmsPluginApplicationTests  : --Application Started--
 smsrec.toString():::::::com.avaal.sms.model.SMSIncoming@4c6bba7d
 Hibernate: insert into dbo.ozekimessagein (id, msg, msgtype, operator, 
  receivedtime, receiver, reference, sender, senttime) values (null, ?, ?, 
 ?, ?, ?, ?, ?, ?)
 2019-03-26 11:32:16.029  WARN 5828 --- [           main] 
  o.h.engine.jdbc.spi.SqlExceptionHelper   : SQL Error: 339, SQLState: S0001
 2019-03-26 11:32:16.029 ERROR 5828 --- [           main] 
 o.h.engine.jdbc.spi.SqlExceptionHelper   : DEFAULT or NULL are not allowed 
as explicit identity values.
  Inside test catch block::::::::::
     org.springframework.dao.InvalidDataAccessResourceUsageException: could 
   not execute statement; SQL [n/a]; nested exception is 
   org.hibernate.exception.SQLGrammarException: could not execute statement
at  org.springframework.orm.jpa.vendor.HibernateJpaDialect.convertHibernateAccessException(HibernateJpaDialect.java:279)
at org.springframework.orm.jpa.vendor.HibernateJpaDialect.translateExceptionIfPossible(HibernateJpaDialect.java:253)
at org.springframework.orm.jpa.AbstractEntityManagerFactoryBean.translateExceptionIfPossible(AbstractEntityManagerFactoryBean.java:527)
at  org.springframework.dao.support.ChainedPersistenceExceptionTranslator.translateExceptionIfPossible(ChainedPersistenceExceptionTranslator.java:61)
at org.springframework.dao.support.DataAccessUtils.translateIfNecessary(DataAccessUtils.java:242)
at org.springframework.dao.support.PersistenceExceptionTranslationInterceptor.invoke(PersistenceExceptionTranslationInterceptor.java:153)
at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:186)
at org.springframework.data.jpa.repository.support.CrudMethodMetadataPostProcessor$CrudMethodMetadataPopulatingMethodInterceptor.invoke(CrudMethodMetadataPostProcessor.java:135)
at

org.springframework.aop.framework.ReflectiveMethodInvocation.proceed（ReflectiveMethodInvocation.java:186）在
org.springframework.aop.interceptor.ExposeInvocationInterceptor.invoke（ExposeInvocationInterceptor.java:93）

在使用ID中的SEQUENCE或AUTO关键字保存时发出问题跟踪：-

`@Id
@GeneratedValue(strategy = GenerationType.SEQUENCE/AUTO)
private long id;`

smsrec.toString():::::::com.avaal.sms.model.SMSIncoming@5d717f19 Hibernate: call next value for hibernate_sequence 2019-03-26 12:29:06.493 WARN 15412 --- [ main] o.h.engine.jdbc.spi.SqlExceptionHelper : SQL Error: 102, SQLState: S0001 2019-03-26 12:29:06.494 ERROR 15412 --- [ main] o.h.engine.jdbc.spi.SqlExceptionHelper : Incorrect syntax near 'value'. Inside test catch block:::::::::: org.springframework.dao.InvalidDataAccessResourceUsageException: could not extract ResultSet; SQL [n/a]; nested exception is org.hibernate.exception.SQLGrammarException: could not extract ResultSet at org.springframework.orm.jpa.vendor.HibernateJpaDialect.convertHibernateAccessException(HibernateJpaDialect.java:279) at org.springframework.orm.jpa.vendor.HibernateJpaDialect.translateExceptionIfPossible(HibernateJpaDialect.java:253)

使用ID为TABLE的关键字保存时发出的跟踪：-

`@Id
@GeneratedValue(strategy = GenerationType.TABLE)
private long id;`



 `smsrec.toString():::::::com.avaal.sms.model.SMSIncoming@69e2fe3b
  Hibernate: select tbl.next_val from hibernate_sequences tbl where 
 tbl.sequence_name=? for update
 2019-03-26 12:33:33.157 ERROR 15896 --- [main] 
  o.hibernate.id.enhanced.TableGenerator   : HHH000351: Could not read or 
  init a hi value com.microsoft.sqlserver.jdbc.SQLServerException: Line 1: FOR UPDATE clause allowed only for DECLARE CURSOR.   at

com.microsoft.sqlserver.jdbc.SQLServerStatement.getNextResult（）上的

com.microsoft.sqlserver.jdbc.SQLServerException.makeFromDatabaseError（SQLServerException.java:259）〜[mssql-jdbc-6.4.0.jre8.jar：na] SQLServerStatement.java:1547）〜[mssql-jdbc-6.4.0.jre8.jar：na]在com.microsoft.sqlserver.jdbc.SQLServerPreparedStatement.doExecutePreparedStatement（SQLServerPreparedStatement.java:548）〜[mssql-jdbc-6.4.0 .jre8.jar：na]`

无法保存具有自动生成的ID的模型记录

0 个答案: