我有一个这样的示例JSON:
}
"vehicles":"4door",
"cars": {
"Toyota":"Camry",
"Ford":"Explorer",
"Nissan":"Altima",
"Jeep":"Wrangler"
},
"color":"red"
}
我正在尝试使用带有JSON的示例JSON和JQuery并使用JSON中的“ cars”数组来创建一个包含2列的HTML表格,这些名称称为“ Make”和“ Model”,而不会使其他项目变色。 “ Make”将是JSON的键,而“ Model”将是键的值。我试图让它看起来像下面这样,但以表格格式。任何帮助或建议,将不胜感激。
Make Model
Toyota Camry
Ford Explorer
Nissan Altima
Jeep Wrangler
答案 0 :(得分:2)
使用Object.keys
获取一组汽车,并使用forEach
循环遍历它们。在jquery中使用append
将行追加到表中
var data = {
"vehicles": "4door",
"cars": {
"Toyota": "Camry",
"Ford": "Explorer",
"Nissan": "Altima",
"Jeep": "Wrangler"
},
"color": "red"
}
var str='';
Object.keys(data.cars).forEach(e => {
str+='<tr><td>' + e + '</td><td>' + data.cars[e] + '</td></tr>';
})
$('#data').append(str)
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<table id="data">
<tr>
<td>Make</td>
<td>Model</td>
</tr>
</table>
答案 1 :(得分:2)
使用Object.keys
会得到keys
的数组,然后您可以对其进行迭代并从对象中获取key
value
并使用模板文字来创建一行并最后附加到table
let cars = {
"Toyota": "Camry",
"Ford": "Explorer",
"Nissan": "Altima",
"Jeep": "Wrangler"
}
let getKeys = Object.keys(cars);
let row = '';
for (let i = 0; i < getKeys.length; i++) {
row += `<tr><td>${getKeys[i]}</td><td>${cars[getKeys[i]]}</td></tr>`
}
$('#carTable').append(row)
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<table id='carTable'>
</table>
答案 2 :(得分:0)
您还可以通过脚本创建整个HTML
<!DOCTYPE html>
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<script>
$(document).ready(function(){
var html = ""
var json = {
"vehicles":"4door",
"cars": {
"Toyota":"Camry",
"Ford":"Explorer",
"Nissan":"Altima",
"Jeep":"Wrangler"
},
"color":"red"
}
html = "<table><thead><th><td>Make</td><td>Model</td></th></thead><tbody>"
for(var x in json.cars){
html+= "<tr><td>"+ x +"</td><td>"+ json.cars[x] +"</td></tr>"
}
html+="</tbody></table>"
$("#main").append(html)
});
</script>
</head>
<body>
<div id="main"></div>
</body>
</html>
答案 3 :(得分:0)
在这里,我看到json格式不正确,也将jsonObject.KeyName
保留在变量中,然后循环保存变量的json。
var obj = {"Toyota":"Camry", "Ford":"Explorer", "Nissan":"Altima", Jeep":"Wrangler"};
for (var key in obj) {
if (obj.hasOwnProperty(key)) {
var val = obj[key];
console.log(val);
}
}
之后,您将以html格式实现。
答案 4 :(得分:0)
var data = {
"vehicles": "4door",
"cars": {
"Toyota": "Camry",
"Ford": "Explorer",
"Nissan": "Altima",
"Jeep": "Wrangler"
},
"color": "red"
};
var cars = data.cars; // for better performance if large table
var tableData = Object.keys(cars).map(item => '<tr><td>' + item + '</td><td>' + cars[item] + '</td></tr>').join('');
$('#main>table').append(tableData)
<div id="main">
<table>
<tr>
<td>Make</td>
<td>Model</td>
</tr>
</table>
</div>