Question

我正在为我的游戏制作开始菜单，但是当我按开始菜单中创建的退出按钮时，它不会退出。我的代码有什么问题吗？

我尝试为退出创建函数，将其放入使用窗口退出按钮退出游戏的代码中，但没有任何效果。

import pygame
import os
pygame.mixer.pre_init()
pygame.mixer.init(44100, 16, 2, 262144)
pygame.init()
from pygame.locals import*


pygame.mixer.music.load(os.path.join(os.getcwd(), 'Sounds', 
'intro.ogg'))
pygame.mixer.music.set_volume(0.3)
pygame.mixer.music.play(-1)  

FPS = 60
white = (255,255,255)
grey = (128,128,128)
black = (0,0,0)
red = (255,0,0)
orange = (255,128,0)
yellow = (255,255,0)
green = (0,255,0)
Lgreen = (128,255,0)
blue = (0,0,255)
Lblue = (0,255,255)
purple = (255,0,255)
pink = (255,0,127)

pygame.display.set_caption('Snake Universe')
Title = pygame.image.load('Graphics/Title.png')
Play = pygame.image.load('Graphics/Play.png')
Option = pygame.image.load('Graphics/Option.png')
Exit = pygame.image.load('Graphics/Exit.png')
LinePX = pygame.image.load('Graphics/LinePX.png')
LineO = pygame.image.load('Graphics/LineO.png')
clock = pygame.time.Clock()
movie = pygame.movie.Movie('Video/bg.mpg')
screen = pygame.display.set_mode((1280, 720))
bgE = pygame.image.load('Graphics/transparent.png')
movie_screen = pygame.Surface(movie.get_size()).convert()


movie.set_display(movie_screen)
movie.play()


y = 235
y1 = 3000



cnt = 0
playing = True
while playing:
    cnt+=1
    if cnt>=1870:
        cnt=0
        movie.rewind()
        movie.play()
    for event in pygame.event.get():
        if event.type == pygame.KEYDOWN:
            if event.key==pygame.K_RETURN:
                if y == 426:
                    movie.stop()
                    playing = False
                    pygame.quit()
                    quit()      
            if event.key == pygame.K_UP:
                y += 1
                if y == 3236:
                    y = 235
                    y1 = 3000
                if y == 236:
                    y = 425
                    y1 = 3000
                if y == 426:
                    y1 =335
                    y = 3235

            if event.key == pygame.K_DOWN:
                y += 1
                if y == 236:
                    y = 3235
                    y1 = 335
                if y == 3236:
                    y1 = 3000
                    y = 425
                if y == 426:
                    y1 = 3000
                    y = 235

            if event.type == pygame.QUIT:
                movie.stop()
                playing = False
                pygame.quit()
                quit()

   screen.blit(movie_screen,(0, 0))
   screen.blit(Title, (360, 0))
   screen.blit(Play, (460, 250))
   screen.blit(Exit, (460, 450))
   screen.blit(LinePX, (482.5, y))
   screen.blit(LineO, (482.5, y1))
   screen.blit(Option, (460, 350))
   screen.blit(bgE, (-100, 0))
   pygame.display.update()
   clock.tick(FPS)

我希望它退出窗口，但是它什么也不做。

Answer 1

只要playing为True，主循环就会运行。

playing = True
while playing:
    # [...]

在处理pygame.QUIT事件时，playing被设置了False，主循环条件失败了：

if event.type == pygame.QUIT:
    playing = False
    # [...]

请注意，pygame.quit()不会终止循环，但是会取消初始化所有pygame模块，如果在应用程序的 middle 中完成，则会导致以下异常

如果要通过键盘输入键pygame.K_KP_ENTER退出应用程序，则在处理pygame.KEYDOWN事件时必须执行相同的操作：

if event.type == pygame.KEYDOWN:
    if event.key==pygame.K_KP_ENTER:
        playing = False

或者您必须在pygame.event.post()前发送pygame.QUIT事件：

if event.type == pygame.KEYDOWN:
    if event.key==pygame.K_KP_ENTER:
        pygame.event.post(pygame.event.Event(pygame.QUIT))

为什么退出窗口按钮可以工作，但游戏中的退出按钮却不能工作？

1 个答案: