Question

我试图将模式形式重定向到我的php脚本，我使用了动作，但是由于某种原因，按钮只是单击并停止。

<form action="action.php" method="post" role="form" target="action.php">

  <div class="form-group">
    <label for="exampleInputEmail1">Email address</label>
    <input class="form-control" id="exampleInputEmail1" placeholder="Enter email" type="email" />
  </div>

  <div class="form-group">
    <label for="exampleInputPassword1">Password</label>
    <input class="form-control" id="exampleInputPassword1" placeholder="Password" type="password" />
  </div>

  <!-- Form submit button -->
  <button class="btn btn-primary" data-target="action.php" data-toggle="button" type="submit">Submit</button>

</form>

</div> <!-- opened somewhere else -->
</div> <!-- opened somewhere else -->

<p>
  <!-- Opens the modal -->
  <button class="btn btn-light" data-target="#surveymodal" data-toggle="modal" type="button">Submit</button>

  <script src="assets/js/jquery.min.js"></script>
  <script src="assets/js/popper.js"></script>
  <script src="bootstrap/js/bootstrap.min.js"></script>
</p>

</body>
</html>

Answer 1

您的“提交”按钮的类型似乎不正确：

<p><button class="btn btn-light" data-target="#surveymodal" data-toggle="modal" type="submit">Submit</button><script src="assets/js/jquery.min.js"></script><script src="assets/js/popper.js"></script><script src="bootstrap/js/bootstrap.min.js"></script></p>

修复以上。

将模式窗体重定向到我的PHP脚本

1 个答案: