获取同一列中所有对应列为空的记录

Question

我的数据看起来像这样

| id             | Failure            
+----------------+-----------
| 1              | null 
| 1              | null  
| 1              | null  
| 1              | abc  
| 1              | null  
| 2              | null
| 2              | null  
| 2              | null  
| 2              | abc  
| 2              | null
| 3              | null
| 3              | null  
| 3              | null  
| 3              | null  
| 3              | null

现在，当所有故障列数据的ID都为空时，我需要获取ID。

预期结果：

| id             | Failure            
+----------------+----------
| 3              | null
| 3              | null  
| 3              | null  
| 3              | null  
| 3              | null

Answer 1

如果只需要ID，请使用聚合：

select id
from t
group by id
having max(failure) is null;

我看不出获得所有重复行的理由。如果您需要它们，那么我建议not exists：

select t.*
from t
where not exists (select 1
                  from t t2
                  where t2.id = t.id and t2.failure is not null
                 );

Answer 2

    Select * 
    from Table 
    where Id not in (select id from Table where failure is not null)