我是Django的新手,已经通过修改一些现有代码来学习。原始代码位于views.py文件中,只需单击一下按钮,该方法便会向浏览器返回HTTP响应对象(称为resp
)。
我希望能够
以及
resp
传递给它(这是因为我正在使用的第三方API需要此HttpResponse
对象才能起作用)。 反正我可以这样做吗?我曾想过将resp
作为context
函数中render()
参数的一部分进行传递,但是我不明白如何从此context
字典中获取值,并且然后将其返回到浏览器。
编辑:这是views.py文件中的代码:
def call(request):
"""Returns TwiML instructions to Twilio's POST requests"""
response = Dial(caller_id=settings.TWILIO_NUMBER)
# If the browser sent a phoneNumber param, we know this request
# is a support agent trying to call a customer's phone
if 'phoneNumber' in request.POST:
response.number(request.POST['phoneNumber'])
else:
# Otherwise we assume this request is a customer trying
# to contact support from the home page
response.client('support_agent')
response = str(response)
probe = response.find(">")
response = response[:probe+1] + "<Response>" + response[probe+1:] + "</Response>"
print('response:', response)
context = {'response': HttpResponse(response)}
return render(request, 'browser_calls/call_in_progress.html', context) # originally HttpResponse(response) was being returned here because that was required for the call to be placed
答案 0 :(得分:0)
您可以做的是使用locals()返回该范围内的所有变量
context = locals()
return render(request, template, context)