我想将完整图像添加到其中一个网格。如何将图像添加到网格单元。以下是component.ts文件:
export interface Tile {
color: string;
cols: number;
rows: number;
text: string;
fontSize: string;
fontFamily: string;
}
@Component({
selector: 'grid-list-dynamic-example',
templateUrl: 'grid-list-dynamic-example.html',
styleUrls: ['grid-list-dynamic-example.css'],
})
export class GridListDynamicExample {
tiles: Tile[] = [
{ text: 'One', cols: 5, rows: 1, color: 'lightblue', fontSize: '20',
fontFamily: 'Rubik'},
{ text: 'Two', cols: 3, rows: 1, color: 'lightgreen', fontSize: '20',
fontFamily: 'Roboto Condensed'},
{ text: 'Three', cols: 2, rows: 2, color: 'lightpink', fontSize:
'25', fontFamily: 'Rubik' },
{ text: 'Four', cols: 3, rows: 1, color: '#DDBDF1', fontSize: '30' ,
fontFamily: 'Roboto Condensed' },
{ text: 'Five', cols: 3, rows: 1, color: 'lightblue', fontSize: '35',
fontFamily: 'Roboto Condensed'},
{ text: 'Six', cols: 2, rows: 1, color: 'lightyellow', fontSize:
'40',fontFamily: 'Rubik' },
];
}
这是html文件:
<mat-grid-list cols="5" rowHeight="20vh" [gutterSize]="'0px'">
<mat-grid-tile
*ngFor="let tile of tiles; let i = index"
[colspan]="tile.cols"
[rowspan]="tile.rows"
[style.background]="tile.color"
[ngStyle]="{'font-size': 'calc(' + tile.fontSize + 'px + 0.5vw)',
'font-family': tile.fontFamily +', sans-serif;'}"
[ngClass]="'tile' + i"
>
{{tile.text}}
</mat-grid-tile>
</mat-grid-list>
这里是stackblitz
我能够将ts文件中的图像添加为颜色,但是该图像只是在网格单元中扩展的图像的一小部分。
答案 0 :(得分:1)
检查已编辑的StackBlitz示例代码。
https://stackblitz.com/edit/angular-sse4n5-qbqb1e
我这样更改了您的界面
export interface Tile {
color: string;
cols: number;
rows: number;
text: string;
fontSize: string;
fontFamily: string;
paddingTop: string;
marginLeft: string;
marginRight: string;
hasImage?: boolean;
imageUrl?: string;
}
在您的html内部标记中:
<ng-container *ngIf="tile.hasImage; else textContainer">
<img [src]="tile.imageUrl"/>
</ng-container>
<ng-template #textContainer>
{{tile.text}}
</ng-template>
如果要将图像显示到任何图块,只需添加两个属性
{... imageUrl: "https://assets.pernod-ricard.com/nz/media_images/test.jpg?hUV74FvXQrWUBk1P2.fBvzoBUmjZ1wct" ,hasImage: true, ...}