Question

我正在尝试在矩形悬停时制作动画。我要达到的目的是使Rectangle在倾斜的情况下占据整个高度，如图所示，但我不想拉直。到目前为止，这是我所做的。我也使用了变换矩阵，但效果不佳

.square {
  position: absolute;
  width: 100px;
  height: 100px;
  top: 50%;
  left: 50%;
  background-color: black;
  border: 1px solid black;
  width: 100px;
  height: 8px;
  background-color: rgba(252, 207, 39, .2);
  -webkit-transform: skew(-25deg);
  -moz-transform: skew(-25deg);
  -ms-transform: skew(-25deg);
  -o-transform: skew(-25deg);
  transform: skew(-25deg);
  transition: transform 1s;
}

.square:hover {
  transform: scaleY(50);
}

<div class="square"></div>

Answer 1

您可以组合高度并按如下所示变换动画：

.square {
  position: absolute;
  width: 100px;
  height: 100px;
  top: 50%;
  left: 50%;
  background-color: black;
  border: 1px solid black;
  box-sizing:border-box;
  width: 100px;
  height: 8px;
  background-color: rgba(252, 207, 39, .2);
  transform: translate(-50%,-50%) skew(-25deg);
  transition: all 1s;
}

.square:hover {
  transform:translate(-50%,-50%) skew(0deg);
  height:100%;
}

body {
 margin:0;
}

<div class="square">
</div>

如果要保持偏斜效果，只需调整高度：

.square {
  position: absolute;
  width: 100px;
  height: 100px;
  top: 50%;
  left: 50%;
  background-color: black;
  border: 1px solid black;
  box-sizing:border-box;
  width: 100px;
  height: 8px;
  background-color: rgba(252, 207, 39, .2);
  transform: translate(-50%,-50%) skew(-25deg);
  transition: all 1s;
}

.square:hover {
  height:100%;
}

body {
 margin:0;
}

<div class="square">
</div>

使用比例尺可以尝试一下（注意变换的顺序）

.square {
  position: absolute;
  width: 100px;
  height: 100px;
  top: 50%;
  left: 50%;
  background-color: black;
  border: 1px solid black;
  box-sizing:border-box;
  width: 100px;
  height: 100%;
  background-color: rgba(252, 207, 39, .2);
  transform: translate(-50%,-50%) skew(-25deg) scaleY(0.1);
  transition: all 1s;
}

.square:hover {
  transform: translate(-50%,-50%) skew(-25deg)  scaleY(1);
}

body {
 overflow:hidden;
 margin:0;
}

<div class="square">
</div>

另一种轮换方式：

.square {
  position: absolute;
  width: 100px;
  height: 100px;
  top: 50%;
  left: 50%;
  background-color: black;
  border: 1px solid black;
  box-sizing:border-box;
  width: 100px;
  height: 100%;
  background-color: rgba(252, 207, 39, .2);
  transform: translate(-50%,-50%) skew(-25deg) rotateX(85deg); /*close to 90deg*/
  transition: all 1s;
}

.square:hover {
  transform: translate(-50%,-50%) skew(-25deg) rotateX(0deg);
}

body {
 overflow:hidden;
 margin:0;
}

<div class="square">
</div>

Answer 2

只需将偏斜再次包含在悬停的过渡中即可。问题是您从偏斜（-25deg）转换为偏斜的默认值0。

确保在标出的scaleY之前包括偏斜；顺序很重要！如果将偏斜度放在scaleY之后，则它将垂直拉伸，从而改变了偏斜度的表观值。

.square {
  position: absolute;
  width: 100px;
  height: 100px;
  top: 50%;
  left: 50%;
  background-color: black;
  border: 1px solid black;
  width: 100px;
  height: 8px;
  background-color: rgba(252, 207, 39, .2);
  -webkit-transform: skew(-25deg);
  -moz-transform: skew(-25deg);
  -ms-transform: skew(-25deg);
  -o-transform: skew(-25deg);
  transform: skew(-25deg);
  transition: transform 1s;
}

.square:hover {
  transform: skew(-25deg) scaleY(50);
}

<div class="square">
</div>

如何对倾斜矩形的高度进行动画处理？

2 个答案: