Question

我正在尝试运行此服务

class PptpService extends VpnService<PptpProfile> {
    @Override
    protected void connect(String serverIp, String username, String password) throws IOException {
        PptpProfile p = getProfile();
        getDaemons().startPptp(serverIp, username, password, p.isEncryptionEnabled());
    }
}

有人可以帮我吗？我已经尝试过了，但是没有运气。

Intent intent = new Intent(this, PptpService.class);
startService(intent);

Answer 1

首先将服务添加到清单：

<?xml version="1.0" encoding="UTF-8"?><RegistryInterface xsi:schemaLocation="http://www.SDMX.org/resources/SDMXML/schemas/v2_0/message SDMXMessage.xsd" xmlns="http://www.SDMX.org/resources/SDMXML/schemas/v2_0/message" xmlns:common="http://www.SDMX.org/resources/SDMXML/schemas/v2_0/common" xmlns:compact="http://www.SDMX.org/resources/SDMXML/schemas/v2_0/compact" xmlns:cross="http://www.SDMX.org/resources/SDMXML/schemas/v2_0/cross" xmlns:generic="http://www.SDMX.org/resources/SDMXML/schemas/v2_0/generic" xmlns:query="http://www.SDMX.org/resources/SDMXML/schemas/v2_0/query" xmlns:structure="http://www.SDMX.org/resources/SDMXML/schemas/v2_0/structure" xmlns:registry="http://www.SDMX.org/resources/SDMXML/schemas/v2_0/registry" xmlns:utility="http://www.SDMX.org/resources/SDMXML/schemas/v2_0/utility" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"><Header><ID>JD014</ID><Test>true</Test><Truncated>false</Truncated><Name xml:lang="en">Trans46302</Name><Prepared>2001-03-11T09:30:47-05:00</Prepared><Sender id="BIS" /></Header><QueryStructureRequest resolveReferences="false"><registry:DataflowRef /></QueryStructureRequest></RegistryInterface>

阅读VpnService

如何运行android服务？

1 个答案: