我如何编写sql查询以获取结果集，从最大时间获取结果集

Question

Name       Longititue   latutute        Time
tharindu    79.94148    6.9748404       00:15:47
shane      79.8630765   6.8910388       13:23:24
shane      79.862815    6.8909349       14:41:29
shane      79.8628665   6.8911084       09:39:33
shane      79.8626956   6.890992        11:00:07
shane      79.8628831   6.89099         11:43:00

我要获得如下结果集

shane      79.862815    6.8909349       14:41:29
tharindu    79.94148    6.9748404       00:15:47

我该如何编写sql查询以获取结果集，并从最大时间获取结果集

Answer 1

您可以尝试使用ROW_NUMBER窗口功能。

SELECT Name,Longititue,latutute,[Time]
FROM (
    SELECT *,ROW_NUMBER() OVER(PARTITION BY Name ORDER BY [Time] DESC) rn
    FROM T
)t1
WHERE rn = 1

Answer 2

您也可以尝试使用相关子查询

select * from tablename a
where Time in (select max(Time) from tablename b where a.name=b.name)

Answer 3

您可以使用相关的子查询

select t.* from table_name t
 where t.[Time]=( select max([Time]) from table_name t1 where t1.Name=t.Name)

Answer 4

这是一种无需正式子查询即可使用ROW_NUMBER的方法：

SELECT TOP 1 WITH TIES
    Name,
    Longititue,
    latutute,
    Time
FROM yourTable
ORDER BY
    ROW_NUMBER() OVER (PARTITION BY Name ORDER BY [Time] DESC);

Demo

Answer 5

您可以使用CTE（通用表表达式）和排名函数来实现此目的。

SQL查询：

WITH CTE AS
(
    SELECT Name,Longititue,latutute,Time,DENSE_RANK() OVER(PARTITION BY Name ORDER BY time desc) as RN
    FROM MaxTime
)
SELECT * FROM CTE
WHERE RN = 1