大家好,第一个帖子在这里! 我目前在使用readfromfile()来计算平均值时遇到一些问题,我的问题是它会打印“粘在一起”的十个数字 像12345678910一样,我不明白如何计算这样的平均值,我尝试了token / 10,它返回0000000000
从这个烂摊子得到平均的建议吗?
我尝试返回%n%s的令牌,该令牌看起来更好,但是当我除以10时,它仍无法给出正确的数字我在做什么错了
package average;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.nio.file.Paths;
import java.util.Formatter;
import java.util.InputMismatchException;
import java.util.Scanner;
public class average {
private static Formatter output;
private static Scanner input;
public static void main(String[] args) {
openFileWrite();
writeToFile();
closeFile();
openFileRead();
readFromFile();
closeFileRead();
}
public static void openFileRead() { // gets file for "read"
try {
input = new Scanner(Paths.get("Numbers.txt"));
} catch (IOException e) {
System.out.println("Unable to read file");
}
}
public static void openFileWrite() { // gets file for "write"
try {
output = new Formatter("Numbers.txt");
} catch (FileNotFoundException e) {
System.out.println("Unable to open file");
}
}
public static void readFromFile() {
while (input.hasNextInt()) {
int token = input.nextInt();
System.out.print(token);
}
}
public static void writeToFile() {
Scanner input = new Scanner(System.in);
System.out.println("Enter 10 numbers");
try {
for (int i = 0; i < 10; i++) {
System.out.println("Another Number Please");
int total = input.nextInt();
output.format("%s%n", total);
}
} catch (InputMismatchException e) {
System.out.println("Please do not enter any letters");
writeToFile();
}
}
//required to close file for write
public static void closeFile() {
output.close();
}
//required to close file for read
public static void closeFileRead() {
input.close();
}
}
答案 0 :(得分:0)
只需将您的readFromFile方法更改为:-
public static void readFromFile() {
double average = 0;
while (input.hasNextInt()) {
int token = input.nextInt();
average+=token;
}
System.out.println("Average ="+average/10);
}