Java:从txt文件计算平均值的问题

时间:2019-03-25 03:05:38

标签: java average read-write

大家好,第一个帖子在这里! 我目前在使用readfromfile()来计算平均值时遇到一些问题,我的问题是它会打印“粘在一起”的十个数字 像12345678910一样,我不明白如何计算这样的平均值,我尝试了token / 10,它返回0000000000

从这个烂摊子得到平均的建议吗?

我尝试返回%n%s的令牌,该令牌看起来更好,但是当我除以10时,它仍无法给出正确的数字我在做什么错了

package average;

import java.io.FileNotFoundException;
import java.io.IOException;
import java.nio.file.Paths;
import java.util.Formatter;
import java.util.InputMismatchException;
import java.util.Scanner;

public class average {

    private static Formatter output;
    private static Scanner input;

    public static void main(String[] args) {

        openFileWrite();
        writeToFile();
        closeFile();
        openFileRead();
        readFromFile();
        closeFileRead();
    }

    public static void openFileRead() {      // gets file for "read"
        try {
            input = new Scanner(Paths.get("Numbers.txt"));
        } catch (IOException e) {
            System.out.println("Unable to read file");
        }
    }

    public static void openFileWrite() {     // gets file for "write"
        try {
            output = new Formatter("Numbers.txt");
        } catch (FileNotFoundException e) {
            System.out.println("Unable to open file");
        }

    }

    public static void readFromFile() {

        while (input.hasNextInt()) {

            int token = input.nextInt();

            System.out.print(token);

        }
    }

    public static void writeToFile() {
        Scanner input = new Scanner(System.in);
        System.out.println("Enter 10 numbers");
        try {
            for (int i = 0; i < 10; i++) {

                System.out.println("Another Number Please");
                int total = input.nextInt();
                output.format("%s%n", total);
            }
        } catch (InputMismatchException e) {
            System.out.println("Please do not enter any letters");
            writeToFile();

        }
    }

    //required to close file for write
    public static void closeFile() {
        output.close();
    }

    //required to close file for read
    public static void closeFileRead() {
        input.close();
    }
}

1 个答案:

答案 0 :(得分:0)

只需将您的readFromFile方法更改为:-

public static void readFromFile() {
        double average = 0;
        while (input.hasNextInt()) {
            int token = input.nextInt();
            average+=token;
        }
        System.out.println("Average ="+average/10);
}