我正在尝试从civicrm_address表中选择某些记录并更新地址解析列。我使用fetchall来检索行,然后在同一循环中,尝试使用geocoder API的结果进行更新,并在update_sql语句中传递civicrm_address.id值。
尝试更新和提交后的行数始终为-1,因此我认为由于某些原因它失败了,但我仍未弄清原因。
import geocoder
import mysql.connector
mydb = mysql.connector.connect(
[redacted]
)
mycursor = mydb.cursor(dictionary=True)
update_cursor = mydb.cursor()
sql = """
select
a.id
, street_address
, city
, abbreviation
from
civicrm_address a
, civicrm_state_province b
where
location_type_id = 6
and
a.state_province_id = b.id
and
street_address is not null
and
city is not null
limit 5
"""
mycursor.execute(sql)
rows = mycursor.fetchall()
print(mycursor.rowcount, "records selected")
for row in rows:
address_id = int(row["id"])
street_address = str(row["street_address"])
city = str(row["city"])
state = str(row["abbreviation"])
myaddress = street_address + " " + city + ", " + state
g = geocoder.arcgis(myaddress)
d = g.json
latitude = d["lat"]
longitude = d["lng"]
update_sql = """
begin work;
update
civicrm_address
set
geo_code_1 = %s
, geo_code_2 = %s
where
id = %s
"""
var=(latitude, longitude, address_id)
print(var)
update_cursor.execute(update_sql, var, multi=True)
mydb.commit()
print(update_cursor.rowcount)
mycursor.close()
update_cursor.close()
mydb.close()
这是一个更简单的脚本:
我已经直接在MySQL工作台中执行了update_sql语句,它成功了。它不适用于Python。
import geocoder
import mysql.connector
try:
mydb = mysql.connector.connect(
[redacted]
)
mycursor = mydb.cursor(dictionary=True)
update_cursor = mydb.cursor()
update_sql = """
begin work;
update
civicrm_address
set
geo_code_1 = 37.3445
, geo_code_2 = -118.5366074
where
id = 65450;
"""
update_cursor.execute(update_sql, multi=True)
mydb.commit()
print(update_cursor.rowcount, "row(s) were updated")
except mysql.connector.Error as error:
print("Failed to update record to database: {}".format(error))
mydb.rollback()
finally:
# closing database connection.
if (mydb.is_connected()):
mydb.close()
答案 0 :(得分:0)
我现在正在工作。我确实删除了“开始工作”语句,但没有删除multi = True,它不起作用。后来我删除了multi = True语句,它起作用了。