Question

我正在尝试从3个表构建查询。销售，商店和物品。目标是获得销量最高的10种产品，并让每种产品展示销售额最低的商店。我有以下查询，但由于它也指向store_desc，因此无法获得最独特的产品。目标是在没有商店描述的情况下获得销量最高的前10种产品，然后获得数量最少的“ a”

select distinct top 10 sum(net_sale) as sales, sum(quantity) 
as a,  sales.item_code,stores.store_desc from sales  join 
stores on stores.store_code=sales.store_code group by 
sales.net_sale, sales.item_code,stores.store_desc  order by 
sales desc

Answer 1

您可以使用以下方法获得每个商店的每种产品的销售额：

select s.store_code, s.item_code, sum(i.quantity) as qty
from sales s
group by s.store_code, s.item_code;

添加一个，我们就可以得出每个商店的总数量：

select s.store_code, s.item_code, sum(i.quantity) as qty,
       sum(sum(i.quantity)) over (partition by s.item_code) as item_qty
from sales s
group by s.store_code, s.item_code;

然后，以此为子查询，我们可以枚举它们：

select s.*,
       dense_rank() over (order by item_qty desc) as item_rank,
       row_number() over (partition by item_code order by qty asc) as item_store_rank
from (select s.store_code, s.item_code, sum(i.quantity) as qty,
             sum(sum(i.quantity)) over (partition by s.item_code) as item_qty
      from sales s
      group by s.store_code, s.item_code
     ) s

然后将其设为子查询。您想要：

where item_rank <= 10 and item_store_rank <= 3

注意：这不考虑不出售某些商品的商店。如果这是一个问题，我建议您提出一个 new 问题，并明确说明如何处理此类情况。

如何获得每种产品的前10名销售产品和最低的3家销售商店

1 个答案: