有没有办法将Sympy方程更改为Sympy表达式？

Question

当用户使用下拉菜单选择要查找的项目时，简单谐波运动中涉及所选项目的所有方程式将重新排列，并以搜索的值作为主题。我使用Sympy方程重新排列了方程。是否有办法将值细分为现在重新排列的方程式或将Sympy方程式更改为Sympy表达式？

这是您可能会发现有用的代码部分：

listCounter = 0
            counter = 0
            equationsWithSearched = []
            symbolsListWithNeededValue = []
            print ("value is", var.get())               #listCounter keeps track of the lists within the 2d array



#symbols
        a,f,x,A,t,v,vmax,amax,Tm,m,k,Tp,l,g,F,Ek,Ep = sp.symbols('a,f,x,A,t,v,vmax,amax,Tm,m,k,Tp,l,g,F,Ek,Ep')         

        #expressions
        aExp = -((2*sp.pi*f)**2)*x
        xExp = A*sp.cos(2*sp.pi*f*t)
        vExp = 2*sp.pi*f*sp.sqrt(A**2-x**2)
        vmaxExp = 2*sp.pi*f*A
        amaxExp = ((2*sp.pi*f)**2)*A
        TmExp = 2*sp.pi*sp.sqrt(m/k)
        TpExp = 2*sp.pi*sp.sqrt(l/g)
        F_Exp = -k*x
        EkExp = 0.5*m*v**2
        EpExp = 0.5*k*x**2                    

        #equations
        aEq = sp.Eq(a, aExp)
        xEq = sp.Eq(x, xExp)
        vEq = sp.Eq(v, vExp)
        vmaxEq = sp.Eq(vmax, vmaxExp)
        amaxEq = sp.Eq(amax, amaxExp)
        TmEq = sp.Eq(Tm, TmExp)
        TpEq = sp.Eq(Tp, TpExp)
        F_Eq = sp.Eq(F, F_Exp)
        EkEq = sp.Eq(Ek, EkExp)
        EpEq = sp.Eq(Ep, EpExp)

        sp.pprint(sp.solve(aEq, x))

        functionsList = [aEq, xEq, vEq, vmaxEq, amaxEq, TmEq, TpEq, F_Eq, EkEq, EpEq]
        for each in functionsList:
            symbolsList.append(each.free_symbols)

        print('length of symbolsList', len(symbolsList))

        for each in symbolsList:
            listCounter += 1
            print(list(each))
            while counter < len(list(each)):
                print(list(each)[counter])
                if str(list(each)[counter]) == var.get():
                    print('True')
                    print(functionsList[listCounter-1])
                    equationsWithSearched.append(functionsList[listCounter-1])
                    symbolsListWithNeededValue.append(each)
                    counter += 1
                else:
                    counter += 1
            counter = 0