Question

我无法让Facebook喜欢接受我的网站网址。使用Facebook开发的工具“URL Linter”，我发现Facebook出现以下错误：“网站无法访问无法访问http://www.domainname.com/categories/blouses.html页面。”

我正在运行一个网站，该网站使用了许多由PHP脚本“即时”创建的重写规则。当请求.html文档时，我使用htaccess将请求解析为PHP文件。

RewriteRule ^(.*).html$  url_controller.php [L]

url-controller.php包含以下代码：

require_once $_SERVER['DOCUMENT_ROOT'].'/lib/config.php';

list($url, $ext) = explode('.html', substr(mysql_real_escape_string($_SERVER['REQUEST_URI']), 1));
list($parent, $child) = explode('/', $url);

$get_product = mysql_query("SELECT p.id FROM product_languages AS pl INNER JOIN products AS p ON pl.product_id = p.id INNER JOIN shop_products AS sp ON sp.product_id = p.id && sp.shop_id = ".$GLOBALS['site_id']." WHERE pl.url_key = '{$url}' && pl.locale = '{$_SESSION['language']}' LIMIT 0,1") or die(mysql_error());

if(mysql_num_rows($get_product)) {
    require_once './pages/view_product.php';
    exit;
}

$get_parent = mysql_query("SELECT c.id FROM categories AS c INNER JOIN shop_categories AS sc ON sc.category_id = c.id && sc.shop_id = ".$GLOBALS['site_id']." INNER JOIN category_languages AS cl ON cl.category_id = c.id && cl.url_key = '{$parent}' && cl.locale = '{$_SESSION['language']}' WHERE parent = 1 && active = 1 LIMIT 0,1");
$get_child = mysql_query("SELECT c.id FROM categories AS c INNER JOIN shop_categories AS sc ON sc.category_id = c.id && sc.shop_id = ".$GLOBALS['site_id']." INNER JOIN category_languages AS cl ON cl.category_id = c.id && cl.url_key = '{$child}' && cl.locale = '{$_SESSION['language']}' WHERE parent = 0 && active = 1 LIMIT 0,1");
if(mysql_num_rows($get_parent) && mysql_num_rows($get_child)) {
    require_once './pages/view_catalog.php';
    exit;
}

$get_cms_page= mysql_query("SELECT p.id FROM cms_pages AS p INNER JOIN shop_cms_pages AS s ON p.id = s.page_id INNER JOIN cms_page_languages AS l ON p.id = l.page_id WHERE s.shop_id = '{$GLOBALS['site_id']}' AND l.url_key = '{$url}' AND p.active = 1 AND l.locale = '{$_SESSION['language']}' LIMIT 0,1") or die(mysql_error());
if(mysql_num_rows($get_cms_page)) {
    require_once './pages/cms_page.php';
    exit;
}

$get_rule = mysql_query("SELECT new_url, status FROM url_rewrite WHERE shop_id = ".$GLOBALS['site_id']." && old_url = '".str_replace('Webshop/','',$url)."' && locale = '{$_SESSION['language']}' LIMIT 0,1") or die(mysql_error());
$fetch_rule = mysql_fetch_array($get_rule);

if(mysql_num_rows($get_rule)) {

     if($fetch_rule['status'] == 301) {
        header ("HTTP/1.1 301 Moved Permanently");
        //fix redirect to /
        if($fetch_rule['new_url'] == '/') {
        header ("Location: ".$fetch_rule['new_url']);
    } else {
        header ("Location: /".$fetch_rule['new_url'].".html");
    }
    exit;
}
elseif($fetch_rule['status'] == 302) {
    header ("Location: /".$fetch_rule['new_url'].".html");
    exit;
}
}

//IF WE GET TO THIS POINT; IT'S NOT BEEN POSSIBLE TO FIND THE REQUESTED URL ANYWHERE IN THE CATALOG
header("HTTP/1.0 404 Not Found");
require_once './pages/error_404.php';
exit;

我很难看到自己做错了什么 - 更糟糕的是，我开始考虑谷歌是否也可能无法访问我的网站？

我希望有人能用他们的经验和知识帮助我：）

提前致谢

Answer 1

如果您转到Google Webmaster Tools，则可以将您的网页设为GoogleBot。这会告诉你谷歌是否有问题。你的代码似乎很好，但我没有花太多时间仔细查看它。

机器人可以到达我的网站吗？ Facebook不能！ PHP中的自定义URL控制器

1 个答案: