Question

让我说一个字符串

string = "Today is going well the dog jumped over the fence. The fence was 
my neighbors asdkhttps://www.urldefence.org/ult/sdfo/90nf3f/lknfksjdn? 
>>>09sdkfjnkbIAS(F89kjfs and here are some more words before another link 
lkm.http//www.someothersite.com/kasd09/3oif/3fo3/3/nffiosuf??? 
DF*SDF***8skdjnf and some more words in the end."

我只想替换包含http链接的长字符串，该字符串由文本前面的空格和后面的空格定义，而http位于中间。

我一直在尝试。

re.sub('\bhttps?\b', '', string)
re.sub('https?.*?', '', string)
re.sub('https?.*?([\s+])', '', string)

连接点时遇到麻烦。

Answer 1

我在正则表达式方面不太好，但是我尝试遵循正则表达式，它使您想要的字符串与空格匹配。因此，如果可以的话，您可以尝试一下。

http.*?([\s])

正则表达式将整个字符串替换为带有空白的http

1 个答案: