Question

我正在尝试找到一个库，我可以使用该库来确定数字是否介于两个数字之间，或者是否必须使用for循环和if条件遍历每个数字

def get_numbers_in_between(li, x, y):
    # x can be bigger than y or vice versa
    if x > y:
        big = x
        small = y
    else:
        big = y
        small = x

    nums_in_between = [n for n in li if (n >= small and n <= big)]
    return nums_in_between


print(get_numbers_in_between([9, 10, 11, 15, 19, 20, 21], 20, 10))

输出：

[10, 11, 15, 19, 20]

是否有一个图书馆会自动找出哪个更大或更小（x，y），然后将列表作为输入并返回一个新的列表，其中包含数字？

Answer 1

如果您从给定的列表开始，并且需要提取满足条件的列表：

lst = [9, 10, 11, 15, 19, 20, 21]
print([n for n in lst if 10 <= n <= 20])

如果您需要所有整数，则只需

list(range(10, 20+1))

如果您需要首先对最大值和最小值进行排序，这是一个选择：

def get_numbers_in_between(li, x, y):
    mx, mn = sorted((x, y))
    return [n for n in li if mx <= n <= mn]

print(get_numbers_in_between(li=[9, 10, 11, 15, 19, 20, 21], x=20, y=10))

Answer 2

您可以使用filter，

>>> nums
[9, 10, 11, 15, 19, 20, 21]
>>> sorted_list = sorted(nums) # easier to find min, max ?
>>> min_, max_ = sorted_list[0], sorted_list[-1]
>>> filter(lambda x: min_ < x < max_, nums)
[10, 11, 15, 19, 20]

在itertools.ifilter中有类似的python2，

>>> import itertools
>>> list(itertools.ifilter(lambda x: 10 <= x <= 20, nums))
[10, 11, 15, 19, 20]

在itertools.filterfalse的{{1}}中，

python3

Answer 3

可以像建议的一样简单：

small = 8
big = 16
nums_in_between = [n for n in li if n in range(small, big)]

Answer 4

尝试一下：

def get_numbers_in_between(l,x,y):
    return [i for i in l if i in range(min(x,y), max(x,y)+1)]

get_numbers_in_between([9, 10, 11, 15, 19, 20, 21], 20, 10)   # [10, 11, 15, 19, 20]

Answer 5

在roganjosh的帮助下-很好！

dat=np.random.randint(0,20,50)
x=5
y=10
ans=dat[(dat>=x) & (dat<y)]
print(ans)

旧（在np.where）：

import numpy as np
dat=np.random.randint(0,20,50)
x=5
y=10
ans=dat[np.where((dat>=x) & (dat<y))]
print(ans)

Answer 6

OP ：自动找出更大或更小的（x，y），然后将列表作为输入并返回包含数字的新列表？

通用方法：

def GetNumbersInBetween(lst, l_Bound, u_Bound):
    n_List = []

    lowerBound = min(l_Bound, u_Bound)   # Get the lower val
    upperBound = max(l_Bound, u_Bound)   # Get the higher val

    for x in lst:
        if x >= lowerBound and x <= upperBound:
            n_List.append(x)
    return n_List

lst = [9, 10, 11, 15, 19, 20, 21]

lowerBound = 20       # intentionally given the wrong value
upperBound = 10       # intentionally given the wrong value

print(GetNumbersInBetween(lst, lowerBound, upperBound))

OR

使用list comprehension：

print([x for x in lst if min(lowerBound,upperBound) <= x <= max(lowerBound,upperBound)])

输出：

[10, 11, 15, 19, 20]

仅打印列表中x和y之间的数字

6 个答案: