Question

我想使用我的API进行更新。为此，我在id的{{1}}中传递了URL。

pk

其中96是http://localhost:8000/api/manager/update/96。现在，我不想在URL中传递primary key，而是在正文中传递id并更新数据。我的网址应该是这样

id

Views.py

http://localhost:8000/api/manager/update

Serializers.py

class ManagerUpdateAPIView(APIView):

    def post(self, request, pk, *args, **kwrgs):

        user = get_object_or_404(User, id=pk)
        userprofile = get_object_or_404(UserProfile, user=pk)

        serializer1 = EmployeeRegisterSerializer(user, data=request.data)
        serializer2 = EmployeeProfileSerializer(userprofile, data=request.data)

        user_role = ACLRoles.objects.get(id=4)

        if serializer1.is_valid() and serializer2.is_valid():

            serializer1.save()
            serializer2.save()

            return Response(status=status.HTTP_200_OK)
        print(serializer1.errors)
        print(serializer2.errors)
        return Response(status=status.HTTP_404_NOT_FOUND)

如何在不通过url传递class EmployeeProfileSerializer(serializers.ModelSerializer): class Meta: model = UserProfile fields = [ 'user_employee_id', 'user_phone', 'user_payroll_id', 'user_hire_date', 'user_pay_rate', 'user_salaried', 'user_excempt', 'user_groups', 'user_state', 'user_city', 'user_zipcode', 'user_status', ] class EmployeeRegisterSerializer(serializers.ModelSerializer): # userprofile = EmployeeProfileSerializer(read_only=True) class Meta: model = User fields = ['first_name','last_name', 'email',]的情况下更新数据。

Answer 1

尝试此代码

class ManagerUpdateAPIView(APIView):

    def post(self, request, *args, **kwrgs): #change is here
        pk = request.data['pk'] #change is here
        user = get_object_or_404(User, id=pk)
        userprofile = get_object_or_404(UserProfile, user=pk)

        serializer1 = EmployeeRegisterSerializer(user, data=request.data)
        serializer2 = EmployeeProfileSerializer(userprofile, data=request.data)

        user_role = ACLRoles.objects.get(id=4)

        if serializer1.is_valid() and serializer2.is_valid():
            serializer1.save()
            serializer2.save()

            return Response(status=status.HTTP_200_OK)
        print(serializer1.errors)
        print(serializer2.errors)
        return Response(status=status.HTTP_404_NOT_FOUND)

，并在POST负载中提供 pk 为

{
    "pk":96,
    "other_data":"other data of your usual payload"
}

不要在URL中传递ID-UpdateApiView

1 个答案: