Question

register_expert

这是user_fields表image

这是var str2="Handrail Ext"; if (fixing.toString().indexOf(str2) === -1 || fixingDig.toString().indexOf(str2) === -1) { console.log("$FixingDig: " + fixingDig + " $Fixing: " + fixing + "InfexOf Result: " + fixing.toString().indexOf(str2) + "."); $('.results #handrails').val(new_posts); $('.wpcf7-form input[name=hidden-post-handrails]').val(new_posts); } else { console.log("$FixingDig: " + fixingDig + " $Fixing: " + fixing + "InfexOf Result: " + fixing.toString().indexOf(str2) + "."); $('.results #handrails').val(0); $('.wpcf7-form input[name=hidden-post-handrails]').val("0"); }表mage

Answer 1

令人信服， userFields是您的模型。

userFields::selectRaw("user_fields.ID_USER_FIELD")
            ->join('register_expert', function($join) use ($city_save){
                $join->on('register_expert.id', 'user_fields.ID_USER_FIELD')
                    ->where('PERMISSION', '1')
                    ->where('city', $city_save)
            })->where('TITLE_USER_FIELD', $text_search_service);

尝试此代码。

Answer 2

我认为Eloquent查询应该看起来像这样，但是正如我在评论中所说，数据库和查询的设计不是很好，所以我认为它不会起作用，只是您对如何使其更复杂有了一个想法雄辩的查询。

$registerExperts = RegisterExperts::whereColumn('ID_USER_FIELD', 'user_fields.ID')
    ->Andwhere('PERMISSION', '=', 1)
    ->limit(1)
    ->select('city')
    ->get();

$users = User::where($registerExperts->get('city') , '=', $city_save)
->andWhere('TITLE_USER_FIELD', '=', $text_search_service)
->get();

这是一篇很好的第一篇文章，了解如何使用Eloquent ORM进行复杂的查询：Dynamic relationships in Laravel using subqueries by Jonathan Reinink

如何在雄辩的Orm中编写复杂的查询？

2 个答案: