Question

以下代码可以实现我想要的功能，但是还有其他更多的python风格吗？

具有以下格式的文件：

...
x_mapUser Number := 0
...
OPEN cur;
 LOOP FETCH cur INTO l_rec;
  EXIT WHEN cur%notfound;
     UPDATE table_U SET USER_ID = V1(c_obj_id) WHERE CURRENT OF cur;

     IF x_mapUser > mapUser-1 AND c_obj_id < count_id Then
            x_mapUser := 0;
            c_obj_id := c_obj_id +1;
     End if;

 x_mapUser := x_mapUser +1;

 END LOOP;
CLOSE cur;

和代码：

key1:value1,key2:value2,...
key21:value21,key22:value22,...
.
EOF

谢谢

Answer 1

一种更快，更Python化的方法是使用csv模块（默认情况下用逗号分隔），然后将项目拆分成双重展平的生成器理解，并馈送到dict中，该表达式接受具有2个元素的元组：

import csv
with open("test.csv",newline="") as f:  # replace ,newline="" by ,"rb" in python 2
    cr = csv.reader(f)
    d = dict(x.split(":") for row in cr for x in row)

print(d)

结果：

{'key1': 'value1', 'key22': 'value22', 'key21': 'value21', 'key2': 'value2'}

非csv版本：

import csv
with open("test.csv") as f:
    d = dict(x.split(":") for line in f for x in line.split(","))

Answer 2

使用varchar：

list.txt：

split()

因此：

key1:value1,key2:value2,key3:value3
key21:value21,key22:value22

输出：

with open("list.txt") as fileObj:
    content = fileObj.readlines()
    # you may also want to remove empty lines
    content = [l.strip() for l in content if l.strip()]

    for line in content:
        for elem in line.split(","):
            print({elem .split(":")[0] : elem.split(":")[1]})

OR

如果要将它们存储在字典中：

{'key1': 'value1'}
{'key2': 'value2'}
{'key3': 'value3'}
{'key21': 'value21'}
{'key22': 'value22'}

列出字典-改进吗？

2 个答案: