Question

我需要编写一个函数，使用while循环从头到尾（不包括最后一个）计算整数的数量。我一直得到0！= 9和0！= 10的输出。代码：

n = 0
k = 1

def div_3_5(start, end):
    global n
    return n
    while (n<k):
        print("Divisible by 3 or 5") 
        if n % 3 == 0 or n % 5 == 0:
            n +=1

我已经坚持了一段时间，请有人帮忙

Answer 1

您几乎在函数的顶部都有return n语句，结果该程序永远不会执行循环

n = 0
k = 5

def div_3_5(start, end):
   flag = False
   number = start
   count = 0
   while flag is False:
      if number % 3 == 0 or number % 5 == 0:
         print("Divisible by 3 or 5")
         print(number)
         count += 1  # So you can see how many times the condition is met

      if number == end:
         flag = True

      number += 1
   print(count)
   return count

div_3_5(n, k)

在Python中0！= 9和0！= 10？

1 个答案: