Question

我正在尝试按周对Redshift中的某些数据进行排序。

select CONCAT(CONCAT('Week', ' '), 
EXTRACT(WEEK FROM sale_date::date + '1 day'::interval)) as date,count(*) as total 
from sales 
where sale_date between ('2019-03-22' - 30) and '2019-03-22' 
group by EXTRACT(WEEK FROM  sale_date::date + '1 day'::interval)
order by 1 asc;

上面的查询工作正常，但是输出如下：

Week 10, 10
Week 11, 20
Week 12, 3
Week 7, 12
Week 8, 3
Week 9, 5

如何修改上面的查询，使输出如下：

Week 7, 12
Week 8, 3
Week 9, 5
Week 10, 10
Week 11, 20
Week 12, 3

Answer 1

您需要为numeric type语句将提取的星期值添加到order by中。因此，转换

order by 1 asc 至

order by cast(EXTRACT(WEEK FROM sale_date::date + '1 day'::interval) as integer)

Redshift-按周对数据进行排序

1 个答案: