Question

我必须进行验证以检查用户输入的应用程序答案。我想删除以下特殊字符的空格（如果有的话）左或之前。

/

，

：

;

-

。

所以最终输出应该是这样的。

例如：

正确答案=> a / b

答案需要接受=>'a / b'，'a / b'，'a / b'，'a / b'，'a / b'

我可以使用replaceOccurrences函数通过替换所有可能的值来做到这一点。有更好的解决方案吗？

Answer 1

使用Range-

删除特殊字符的空格之前和之后

    let specialChars = ["/",":", ",", ";", "-", "."]
    let aString = " AB / CD EF ; G : H , MN O - P"
    var trimmedString = aString.trimmingCharacters(in: .whitespacesAndNewlines)

    for specialChar in specialChars {

        if let beforeSpacerange = trimmedString.range(of: " \(specialChar)") {
            trimmedString.replaceSubrange(beforeSpacerange, with: specialChar)
        }
        if let afterSpacerange = trimmedString.range(of: "\(specialChar) ") {
            trimmedString.replaceSubrange(afterSpacerange, with: specialChar)
        }

    }

    debugPrint(trimmedString)

希望它会对您有所帮助。让我知道您是否还有任何问题。

编码愉快。

Answer 2

您可以使用正则表达式将字符串替换为[ ]+{special_char}和{special_char}[ ]+格式。

修改

将"."更新为"\\."

感谢ielyamani

例如

func acceptedAnswer(of answer: String) -> String {
    let specialChars = ["/", ":", ",", ";", "-", "\\."]
    var newAnswer = answer.trimmingCharacters(in: .whitespacesAndNewlines)
    for specialChar in specialChars {
        let beforeCharRegex = "[ ]+" + specialChar
        let afterCharRegex = specialChar + "[ ]+"
        newAnswer = newAnswer.replacingOccurrences(of: beforeCharRegex, with: specialChar, options: .regularExpression, range: nil)
        newAnswer = newAnswer.replacingOccurrences(of: afterCharRegex, with: specialChar, options: .regularExpression, range: nil)
    }
    return newAnswer
}

print(acceptedAnswer(of: " apple /   orange     : banana    "))
// apple/orange:banana

Answer 3

您可以使用replacingOccurrences，它将仅用该符号将您的符号替换为空格。为此，您可以使用递归方法

func removed(in text: String) -> String {
    let symbols = ["/", ",", ":", ";", "-", "."]
    var newText = text
    symbols.forEach { newText = replaced(in: newText, for: $0) }
    return newText
}

func replaced(in text: String, for symbol: String) -> String {
    var newText = text
    let left = " \(symbol)"
    newText = newText.replacingOccurrences(of: left, with: symbol)
    let right = "\(symbol) "
    newText = newText.replacingOccurrences(of: right, with: symbol)
    return newText != text ? replaced(in: newText, for: symbol) : newText
}

用法：

let string = "Apple / Orange Swift    .   ObjC Moon  : Sun USA - UK"
print(removed(in: string))

Apple/Orange Swift.ObjC Moon:Sun USA-UK

Swift-iOS：删除任何特殊字符前后的字符串中的空格

3 个答案: