Question

我已经发布了数组JSON。我已经尝试了很多次，但是没有用。

//我将代码放到那里，请帮助我调试它。

字符串json

> {"resultUser":[{"username":"quyennv","email":"quyencl@hotmail.com","userlevel":0,"datecreate":"20/03/2019
> 12:00:00
> AM","status":1},{"username":"sample","email":"sameple@hotmail.com","userlevel":1,"datecreate":"20/03/2019
> 12:00:00 AM","status":1}]}

这是数组中view元素的代码

var datax = {"resultUser":[{"username":"quyennv","email":"quyencl@hotmail.com","userlevel":0,"datecreate":"20/03/2019 12:00:00 AM","status":1},{"username":"sample","email":"sameple@hotmail.com","userlevel":1,"datecreate":"20/03/2019 12:00:00 AM","status":1}]};

var userTbl = $('#listUser tbody').empty();                  
$.each(datax.resultUser,function (index) {  
    index += 1;
    userTbl.append('<tr><td>' + this.username + '</td><td>'  
        + this.email + '</td><td>' + this.userlevel + '</td><td>'  
        + this.datecreate + '</td><td>' + this.status + '</td></tr>');  

});

table,td{
 border:1px solid #000;
}

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

<body>
<table id="listUser">
<thead ><tr><td>Username</td><td>Email</td><td>User Level</td><td>Date Created</td><td>User status</td></tr></thead>
<tbody>
</tbody>
</table>
</body>

请帮助我解决此问题。非常感谢

===== 更新。我需要每个循环内的更多details元素将 datax 更改为 datax.resultUser

Answer 1

在$ .each中将 data 更改为 datax.resultUser ，以遍历resultUser数组

var datax = {"resultUser":[{"username":"quyennv","email":"quyencl@hotmail.com","userlevel":0,"datecreate":"20/03/2019 12:00:00 AM","status":1},{"username":"sample","email":"sameple@hotmail.com","userlevel":1,"datecreate":"20/03/2019 12:00:00 AM","status":1}]};

var userTbl = $('#listUser tbody').empty();                  
$.each(datax.resultUser,function (index) {  
    index += 1;
    userTbl.append('<tr><td>' + this.username + '</td><td>'  
        + this.email + '</td><td>' + this.userlevel + '</td><td>'  
        + this.datecreate + '</td><td>' + this.status + '</td></tr>');  

});

table,td{
 border:1px solid #000;
}

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

<body>
<table id="listUser">
<thead ><tr><td>Username</td><td>Email</td><td>User Level</td><td>Date Created</td><td>User status</td></tr></thead>
<tbody>
</tbody>
</table>
</body>

Answer 2

df['ideal_weight'] = np.where(((df.fats > np.percentile(df.fats, 25)) & (df.fats < np.percentile(df.fats, 50))), 'yes', 'no')

data.resultUser仅数组，您只需对其进行迭代

如何通过jQuery获取JSON的数组多维维度上的子元素的值

2 个答案: