Question

我对此很陌生，如果这是一个非常简单的问题，请对不起。当我尝试使用多选项html表单插入mysql时，它只会插入从下拉列表中选择的最后一个选项，但是会多次插入该选项。

HTML

<form action ="test_page.php" method="post">
     <select name= fruit[] size="8" multiple>
         <option value ="Apples" >Apples</option>
         <option value ="Oranges" >Oranges</option>
         <option value ="Bananas" >Bananas</option>
         <option value ="Grapes" > Grapes </option>
         <option value ="Strawberries"> Strawberries</option>
    </select>
    <br><br>
    <input type="submit" name="submit" value="Submit" />
</form>`

这是PHP

<?php

foreach ($_POST["fruit"] as $favourite)
{
    $sql = "INSERT INTO Fruit_table (Apples, Oranges, Bananas, Grapes) VALUES ('$favourite','$favourite','$favourite', '$favourite');";
}

if ($conn->multi_query($sql) === TRUE)  {
    echo "New record created successfully";
} else {
    echo "Error: " . $sql . "<br>"  .  $conn->error;
}

$conn->close();
?>

Answer 1

我发现了您的问题！因此，实际上您只在执行最后一个时才使用$sql多次设置foreach。

像这样；

foreach ($_POST["fruit"] as $favourite)
{
$sql = "INSERT INTO Fruit_table (Apples, Oranges, Bananas, Grapes) 
 VALUES ('$favourite','$favourite','$favourite', '$favourite');";
}

这是完整的有效代码！

<?php

foreach ($_POST["fruit"] as $favourite)
{
$sql = "INSERT INTO Fruit_table (Apples, Oranges, Bananas, Grapes) 
 VALUES ('$favourite','$favourite','$favourite', '$favourite');";

if ($conn->query($sql) === TRUE)  {
    echo "New record created successfully";
} else {
    echo "Error: " . $sql . "<br>"  .  $conn->error;
}
}

$conn->close();
?>

所以，我只更改了foreach()的位置。现在应该可以使用！

Answer 2

在名称周围加上引号。

从此：

<select name=fruit[] size="8" multiple>

对此：

<select name="fruit[]" size="8" multiple>

无法使用php

2 个答案: