我有以下数据
ID Difference in days between 2 consecutive orders
abc. 2
abc. 3
abc. 7
xyz. 4
xyz. 5
我希望结果为
ID . Avg time difference between 2 orders
abc. 3(=12/4)
xyz. 4.5(=(4+5)/2
答案 0 :(得分:0)
您可以使用AVG和分组依据
select id, avg(Difference )
from my_table
group by id