我正在编写一个小脚本,以浏览版权声明电子邮件的大文件夹并查找相关信息(IP和时间戳)。我已经找到了一些小的格式化障碍的方法(有时IP和TS位于不同的行,有时在同一行,有时在不同的地方,时间戳有4种不同的格式,等等。)
我遇到一个奇怪的问题,我正在解析的一些文件在一行的中间喷出了奇怪的字符,破坏了我对readline()的解析返回。 在文本编辑器中阅读时,该行看起来很正常,但readline()会在IP中间读取一个'='和两个'\ n'字符。
例如
Normal return from readline():
"IP Address: xxx.xxx.xxx.xxx"
Broken readline() return:
"IP Address: xxx.xxx.xxx="
The next two lines after that being:
""
".xxx"
有什么想法可以解决这个问题吗?我真的无法控制可能导致此问题的原因,我只是需要处理而不会太疯狂。
相关功能,以供参考(我知道那是一团糟):
def getIP(em):
ce = codecs.open(em, encoding='latin1')
iplabel = ""
while not ("Torrent Hash Value: " in iplabel):
iplabel = ce.readline()
ipraw = ce.readline()
if ("File Size" in ipraw):
ipraw = ce.readline()
ip = re.findall( r'[0-9]+(?:\.[0-9]+){3}', ipraw)
if ip:
return ip[0]
ce.close()
else:
ipraw = ce.readline()
ip = re.findall( r'[0-9]+(?:\.[0-9]+){3}', ipraw)
if ip:
return ip[0]
ce.close()
else:
return ("No IP found in: " + ipraw)
ce.close()
答案 0 :(得分:0)
已解决,如果其他任何人都遇到类似的问题,请将每行另存为字符串,将它们合并在一起,然后重新生成(.sub()),并记住\ r和\ n字符。我的解决方案有点意大利面,但可以防止对每个文件执行不必要的正则表达式:
df16.pivot(index="Fecha inicio", columns="Delito",
values="No delitos").plot()
plt.show()
答案 1 :(得分:0)
您正在处理的至少某些电子邮件似乎已被编码为quoted-printable。
此编码用于使8位字符数据可在7位(仅ASCII)系统上传输,但它也强制使用76个字符的固定行长。这是通过插入由“ =”和行尾标记组成的软换行符实现的。
Python提供了quopri模块来处理来自quoted-printable的编码和解码。从带引号的可打印数据中解码数据将删除这些换行符。
例如,让我们使用问题的第一段。
>>> import quopri
>>> s = """I'm writing a small script to run through large folders of copyright notice emails and finding relevant information (IP and timestamp). I've already found ways around a few little formatting hurdles (sometimes IP and TS are on different lines, sometimes on same, sometimes in different places, timestamps come in 4 different formats, etc.)."""
>>> # Encode to latin-1 as quopri deals with bytes, not strings.
>>> bs = s.encode('latin-1')
>>> # Encode
>>> encoded = quopri.encodestring(bs)
>>> # Observe the "=\n" inserted into the text.
>>> encoded
b"I'm writing a small script to run through large folders of copyright notice=\n emails and finding relevant information (IP and timestamp). I've already f=\nound ways around a few little formatting hurdles (sometimes IP and TS are o=\nn different lines, sometimes on same, sometimes in different places, timest=\namps come in 4 different formats, etc.)."
>>> # Printing without decoding from quoted-printable shows the "=".
>>> print(encoded.decode('latin-1'))
I'm writing a small script to run through large folders of copyright notice=
emails and finding relevant information (IP and timestamp). I've already f=
ound ways around a few little formatting hurdles (sometimes IP and TS are o=
n different lines, sometimes on same, sometimes in different places, timest=
amps come in 4 different formats, etc.).
>>> # Decode from quoted-printable to remove soft line breaks.
>>> print(quopri.decodestring(encoded).decode('latin-1'))
I'm writing a small script to run through large folders of copyright notice emails and finding relevant information (IP and timestamp). I've already found ways around a few little formatting hurdles (sometimes IP and TS are on different lines, sometimes on same, sometimes in different places, timestamps come in 4 different formats, etc.).
要正确解码,需要处理整个消息正文,这与您使用readline
的方法相冲突。解决此问题的一种方法是将解码后的字符串加载到缓冲区中:
import io
def getIP(em):
with open(em, 'rb') as f:
bs = f.read()
decoded = quopri.decodestring(bs).decode('latin-1')
ce = io.StringIO(decoded)
iplabel = ""
while not ("Torrent Hash Value: " in iplabel):
iplabel = ce.readline()
...
如果您的文件包含完整的电子邮件(包括标题),则使用email模块中的工具将自动处理此解码。
import email
from email import policy
with open('message.eml') as f:
s = f.read()
msg = email.message_from_string(s, policy=policy.default)
body = msg.get_content()