我想从两个对象数组中添加给定的点,并在student_id bcoz的帮助下在单个对象数组中显示,在两个对象Student_id数组中都是唯一的。
Array
(
[0] => stdClass Object
(
[student_id] => 91
[given_points] => 8
[bonus_points] => 2
)
[1] => stdClass Object
(
[student_id] => 91
[given_points] => 6
[bonus_points] => 1
)
)
Array
(
[0] => stdClass Object
(
[student_id] => 95
[given_points] => 9
[bonus_points] => 1
)
[1] => stdClass Object
(
[student_id] => 95
[given_points] => 9
[bonus_points] => 1
)
)
答案 0 :(得分:0)
$sum = 0;
foreach($array as $key => $value)
{
sum+=$array[$key]['given_points'];
}
echo $sum //prints sum
答案 1 :(得分:0)
$sum_points = 0;
$sum_student_id=0;
foreach($array as $key=>$value){
if(isset($value->given_points))
$sum_points += $value->given_points;
if(isset($value->student_id))
$sum_student_id += $value->student_id;
}
echo $sum_points;
echo $sum_student_id;
因为这是一个stdClass数组,所以请使用-> 而不是方括号 ['']
还有另一种方法:(PHP> = 5.5)
$sum_points = array_sum(array_column($array, 'given_points'));
$sum_student_ids = array_sum(array_column($array, 'student_id'));
答案 2 :(得分:0)
$array = [
0 => ['student_id' => 91,
'given_points' => 8,
'bonus_points' => 2
],
1 => ['student_id' => 91,
'given_points' => 8,
'bonus_points' => 2
],
2 => ['student_id' => 92,
'given_points' => 8,
'bonus_points' => 2
],
3 => ['student_id' => 93,
'given_points' => 8,
'bonus_points' => 2
]
];
foreach ($array as $row) {
if (isset($newArray[$row['student_id']])) {
$newArray[$row['student_id']] = $newArray[$row['student_id']] + $row['given_points'];
} else {
$newArray[$row['student_id']] = $row['given_points'];
}
}
print_r($newArray);
您可以尝试类似上面的代码。基本上,由于student_id是表的唯一标识符,因此您希望基于此表实现逻辑,然后使其成为新的数组键字段。
上面的代码将使用尽可能多的记录,并且输出的数组将如下所示:
Array
(
[91] => 16
[92] => 8
[93] => 8
)
添加了ID为91的2个用户,其余的是在单独的数组字段中的唯一用户。