Question

我需要帮助！我需要创建10个子目录：A1，A2，...，A10。每个子目录包含一个名为 position 的文件，其内容为：

2.22222  0.44444  1.58810
5.77778  1.5556  0.41190

每个文件的末尾包含一个与子目录相对应的位置：例如：在目录A1中的位置：

2.22222  0.44444  1.58810
5.77778  1.55556  0.41190
1.00000  1.00000  1.00000

目录A2中的

位置包含

2.22222  0.44444  1.58810
5.77778  1.55556  0.41190
2.00000  2.00000  2.00000

在目录A3中的相似位置包含：

2.22222  0.44444  1.58810
5.77778  1.55556  0.41190
3.00000  3.00000  3.00000

以此类推。我尝试通过python进行编码，但是当出现错误时它无法正常工作 IOError：[Errno 21]是目录：

import os
content += u"0.22222  0.44444  0.58810"
content += u"0.77778  0.55556  0.41190" 
num = 0
for i in range(0, 10)
   num = num + 1
   subdirectory = str("A")+str(num)
   os.mkdir (subdirectory)
   filename = str(position)
   for ip in open(filename):
   with open (os.path.join(subdirectory)) as ip:
   fp.write(content)
   for ip in open(filename):
      with open (os.path.join(subdirectory)) as ip:
          ft.write"{:.5f}  {:.5f}  {:.5f} ".format(num, num, num)

请帮助我调试此代码！

Answer 1

您的第一个for循环在“ for i in range（0，10）”位之后需要一个冒号。

for i in range(0, 10)
   num = num + 1

有可能成为

for i in range (0, 10):
    num += 1

我认为我唯一可以看到的错误是冒号。

num += 1

所做的事情与您所做的完全相同，这是一种很好且更快的编码方法。您的缩进也不正确，因此如果您也将其整理出来，那应该没问题。

Answer 2

它可以在我的机器上工作。

import os
dir_path = os.path.dirname(os.path.realpath(__file__))
# print(dir_path)     #here, you will choose the working directory. currently, it is the same as your python file.
# for readibility, you can use multi-line string here.
content = '''
2.22222  0.44444  1.58810
5.77778  1.5556  0.41190
'''
for i in range(0, 10):
   foldername = dir_path+"\\"+'a'+str(i+1)
   os.makedirs(foldername)
   # use encoding 'utf-8' if you would like so.
   with open(foldername+"\\position.txt",'w',encoding='utf-8') as 
       innerfile:
       innerfile.write(content)
       innerfile.write('{:.5f}  {:.5f}  {:.5f}'.format(i+1,i+1,i+1))

Answer 3

pathlib使得它更容易思考，因为它完成了所有自身路径名的连接。此代码片段将创建目录（如果不存在）并创建文件（如果文件不存在），并将2.00000 2.00000 2.00000...字符串附加到每个目录中。

from pathlib import Path
dirnames = {'A01': 1, 'A02': 2, 'A03': 3, 'A10': 10}
basePath = Path('./foobar') # base path to work in
myFile = Path('file.txt') # name of each file to append to
repeats = 4 # number of times to repeat the appended value string
for name, value in dirnames.items():
    # Create the file    
    myName = Path(basePath/name)

    # Make the directories
    try:
        myName.mkdir()
    except FileExistsError:
        print('{} exists, skipping'.format(myName))

    # make the string that will be appended to each file
    myString = ''
    print(myFile)
    for i in range(0, repeats):
        myString = myString + ('{:.5f} '.format(value))
    myString + '\n'

    fileName = Path(myName/myFile) # set the file name 

    # write the string out to the file
    with fileName.open(mode='a') as dataOut:
        dataOut.write(myString)

python在每个子文件夹中创建一个文件

3 个答案: