Question

我正在按照这里的说明进行操作：

https://testnet.bitmex.com/app/wsAPI

并且我已经确认以下Python实现有效（即，从我的角度来看，没有网络问题），因为：

python wsdump.py \
  wss://testnet.bitmex.com/realtime

> {"op":"subscribe","args":["orderBookL2_25:XBTUSD"]}

产生

{"success":true,"subscribe":"orderBookL2_25:XBTUSD","request":{"op":"subscribe","args":["orderBookL2_25:XBTUSD"]}}

我试图修改大猩猩示例代码以组合基本客户端：

package main

import (
    "encoding/json"
    "flag"
    "fmt"
    "log"
    "net/url"
    "os"
    "os/signal"
    "time"

    "github.com/gorilla/websocket"
)

var addr = flag.String("addr", "testnet.bitmex.com", "http service address")

func main() {
    flag.Parse()
    log.SetFlags(0)

    interrupt := make(chan os.Signal, 1)
    signal.Notify(interrupt, os.Interrupt)

    u := url.URL{Scheme: "wss", Host: *addr, Path: "/realtime"}
    log.Printf("connecting to %s", u.String())

    c, _, err := websocket.DefaultDialer.Dial(u.String(), nil)
    if err != nil {
        log.Fatal("dial:", err)
    }
    defer c.Close()

    done := make(chan struct{})

    go func() {
        defer close(done)
        for {
            _, message, err := c.ReadMessage()
            if err != nil {
                log.Println("read:", err)
                return
            }
            log.Printf("recv: %s", message)
        }
    }()

    type commandStruct struct {
        Op   string   `json:"op"`
        Args []string `json:"args"`
    }
    command := &commandStruct{
        Op:   "subscribe",
        Args: []string{"orderBookL2_25:XBTUSD"}}
    json, _ := json.Marshal(command)
    stringJSON := string(json)
    fmt.Println("JSON:", stringJSON)
    connectionErr := c.WriteJSON(stringJSON)
    if connectionErr != nil {
        log.Println("write:", connectionErr)
    }

    for {
        select {
        case <-done:
            return
        case <-interrupt:
            log.Println("interrupt")

            // Cleanly close the connection by sending a close message and then
            // waiting (with timeout) for the server to close the connection.
            err := c.WriteMessage(websocket.CloseMessage, websocket.FormatCloseMessage(websocket.CloseNormalClosure, ""))
            if err != nil {
                log.Println("write close:", err)
                return
            }
            select {
            case <-done:
            case <-time.After(time.Second):
            }
            return
        }
    }
}

我的程序将以下内容打印到控制台：

{"op":"subscribe","args":["orderBookL2_25:XBTUSD"]}

与上面的Python示例中的JSON相同。但是然后我收到一条错误消息：

recv: {"status":400,"error":"Unrecognized request. See the docs or send 'help' for more details.","meta":{},"request":"{\"op\":\"subscribe\",\"args\":[\"orderBookL2_25:XBTUSD\"]}"}

为什么我得到不同的结果？

Answer 1

问题是应用程序将值双重编码为JSON：

对json.Marshal(command)的调用将command结构编码为JSON：

{"op":"subscribe","args":["orderBookL2_25:XBTUSD"]}

调用c.WriteJSON(stringJSON)将该文本编码为JSON并将其写入网络。双重编码的JSON是：

"{\"op\":\"subscribe\",\"args\":[\"orderBookL2_25:XBTUSD\"]}"

改为使用以下代码：

connectionErr := c.WriteJSON(command)

将golang与大猩猩websocket库一起使用，为什么WriteJson返回错误？

1 个答案: