如何打破感测条件内的while循环

时间:2019-03-20 23:53:51

标签: c arduino arduino-uno

我的伪代码的本质如下(我将其简化为安排更简单的答案):

if (vibrate == 1){ //this is the input sensing to the arduino. 
  //It is either 1 or 0
  //constantly run a while loop IF vibrate ==1
  i=51;
  while(vibrate ==1){
     analogWrite(Motor,i); //constantly outputing a pulse of increasing magnitude
     delay(10); //delay it for a certain period of time
     i=i+50; //increment i 
     if (i>=255){
       i=51;
     }
  }
}
else{ //do something else. Has it's own functions}

现在,振动从传感器进入。如果振动为1,我会自动希望输出一个斜坡脉冲(即while循环)。但是,如果振动改变了它的值(即变为零),我希望不触发while循环,如果它被触发,我想退出while循环。我面临的问题是,振动会在while循环之外进行自我更新,因此我将得到一个无限循环。有没有更好的方法来合并这个?我也无法在while循环中更新振动值,因为我也需要检查更大的“ if”。

2 个答案:

答案 0 :(得分:2)

在循环内,您可以调用break;以在您调用的循环外继续执行。

答案 1 :(得分:1)

更新while循环中的振动变量。您无需使用 break

void updateVibrate(){
       //UPDATE THE VIBRATE VARIABLE
    }

    if (vibrate == 1){ //this is the input sensing to the arduino. 
      //It is either 1 or 0
      //constantly run a while loop IF vibrate ==1
      i=51;
      while(vibrate ==1){
         analogWrite(Motor,i); //constantly outputing a pulse of increasing magnitude
         delay(10); //delay it for a certain period of time
         i=i+50; //increment i 
         if (i>=255){
           i=51;
         }
       updateVibrate();//Call function which will update the vibrate (Global) Variable
      }
    }
    else{ //do something else. Has it's own functions}

或者,当迭代次数固定时,可以使用带有break语句的for循环