我正在尝试根据客户和日期范围获取数组中所有“数量”元素的总和。我希望输出数组（最终结果）看起来像这样……
Array
(
[0] => stdClass Object
(
[company_name] => Yeung's Architects
[customer_id] => 3
[name] => Billable Expenses Income
[due_date] => 2019-04-19 00:00:00
[amount] => 1543.64
[account_id] => 75
)
[1] => stdClass Object
(
[company_name] => Clement's Cleaners
[customer_id] => 8
[name] => Billable Expenses Income
[due_date] => 2019-04-19 00:00:00
[amount] => 2177.27
[account_id] => 75
)
[2] => stdClass Object
(
[company_name] => Clement's Cleaners
[customer_id] => 8
[name] => Billable Expenses Income
[due_date] => 2019-05-19 00:00:00
[amount] => 295.45
[account_id] => 75
)
)
这是我正在使用的sql调用...
SELECT c.company_name
, i.customer_id
, a.name
, i.due_date
, li.amount
, li.account_id
FROM invoices i
JOIN customers c
ON c.customer_id = i.customer_id
JOIN invoices_line_items li
ON li.guid = i.guid
AND li.invoice_id = i.invoice_id
JOIN accounts a
ON a.guid = li.guid
AND a.account_id = li.account_id
WHERE i.guid = ?
AND i.date >= "'.$firstOfThisMonth.'" ',array($guid));
从sql调用开始生成的数组开始使用...
Array
(
[0] => stdClass Object
(
[company_name] => Yeung's Architects
[customer_id] => 3
[name] => Billable Expenses Income
[due_date] => 2019-04-19 00:00:00
[amount] => 1362.73
[account_id] => 75
)
[1] => stdClass Object
(
[company_name] => Yeung's Architects
[customer_id] => 3
[name] => Billable Expenses Income
[due_date] => 2019-04-19 00:00:00
[amount] => 180.91
[account_id] => 75
)
[2] => stdClass Object
(
[company_name] => Clement's Cleaners
[customer_id] => 8
[name] => Billable Expenses Income
[due_date] => 2019-04-19 00:00:00
[amount] => 177.27
[account_id] => 75
)
[3] => stdClass Object
(
[company_name] => Clement's Cleaners
[customer_id] => 8
[name] => Billable Expenses Income
[due_date] => 2019-05-19 00:00:00
[amount] => 159.09
[account_id] => 75
)
[4] => stdClass Object
(
[company_name] => Clement's Cleaners
[customer_id] => 8
[name] => Billable Expenses Income
[due_date] => 2019-05-19 00:00:00
[amount] => 136.36
[account_id] => 75
)
[5] => stdClass Object
(
[company_name] => Clement's Cleaners
[customer_id] => 8
[name] => Services
[due_date] => 2019-04-19 00:00:00
[amount] => 2000.00
[account_id] => 1
)
)
我目前用于尝试根据客户ID和发票月份对所有金额求和的代码。
$output = array($data[0]); $c = 1;
foreach ($data as $key => $value) {
if ($key > 0) {
if (in_array($value->customer_id,array_column($output, 'customer_id'))) {
$valueDate = substr($value->due_date,0,7);
foreach ($output as $k => $v) {
if ($v->customer_id == $value->customer_id) {
$vDate = substr($v->due_date,0,7);
if ($vDate == $valueDate) {
$output[$k]->amount = $output[$k]->amount + $value->amount;
} else {
$output[$c] = $value;
$c++;
}
}
}
} else {
$output[$c] = $value;
$c++;
}
}
}
return $output;
这是我从上述代码中得到的最终结果...
Array
(
[0] => stdClass Object
(
[company_name] => Yeung's Architects
[customer_id] => 3
[name] => Billable Expenses Income
[due_date] => 2019-04-19 00:00:00
[amount] => 1543.64
[account_id] => 75
)
[1] => stdClass Object
(
[company_name] => Clement's Cleaners
[customer_id] => 8
[name] => Billable Expenses Income
[due_date] => 2019-04-19 00:00:00
[amount] => 2177.27
[account_id] => 75
)
[2] => stdClass Object
(
[company_name] => Clement's Cleaners
[customer_id] => 8
[name] => Billable Expenses Income
[due_date] => 2019-05-19 00:00:00
[amount] => 295.45
[account_id] => 75
)
[3] => stdClass Object
(
[company_name] => Clement's Cleaners
[customer_id] => 8
[name] => Billable Expenses Income
[due_date] => 2019-05-19 00:00:00
[amount] => 136.36
[account_id] => 75
)
[4] => stdClass Object
(
[company_name] => Clement's Cleaners
[customer_id] => 8
[name] => Services
[due_date] => 2019-04-19 00:00:00
[amount] => 2000.00
[account_id] => 1
)
[5] => stdClass Object
(
[company_name] => Clement's Cleaners
[customer_id] => 8
[name] => Services
[due_date] => 2019-04-19 00:00:00
[amount] => 2000.00
[account_id] => 1
)
)
前3个键是正确的结果，但是随后添加了3个额外的键，我不确定它们是如何添加的。我的大脑现在坏了，请有人帮我，任何帮助将不胜感激。
答案 0 :(得分：1)
所以，如果我要关注的是，您只想按company_name进行分组，或者还有其他维度？实际上，在SQL中执行此操作非常简单。
使用聚合函数，总和和按公司字段分组进行查询。您可以在下面看到很少的更改。
SELECT c.company_name
, i.customer_id
, a.name
, i.due_date
, SUM(li.amount)
, AVG(li.amount)
, li.account_id
FROM invoices i
JOIN customers c
ON c.customer_id = i.customer_id
JOIN invoices_line_items li
ON li.guid = i.guid
AND li.invoice_id = i.invoice_id
JOIN accounts a
ON a.guid = li.guid
AND a.account_id = li.account_id
WHERE i.guid = ?
AND i.date BETWEEN :startDate AND :endDate
GROUP BY i.customer_id
更多信息可在此处找到：https://dev.mysql.com/doc/refman/8.0/en/group-by-functions.html和此处https://dev.mysql.com/doc/refman/5.7/en/group-by-handling.html
如果需要，您可以添加第二个GROUP BY（实际需要的数量）。假设您要查询一个“按月按客户求和”的查询。你会做类似...
GROUP BY i.customer_id, DATE_FORMAT(i.due_date, '%Y-%m')
WITH ROLLUP在调试中很有用。