带有标志的Bash函数，其中任一是可选的？

Question

我试图编写一个bash函数来本质上别名删除本地和远程git分支。我希望它像这样运行：

$ db -r <branch_name> // deletes remote branch with name <branch_name>
$ db -l <branch_name> // deletes local branch with name <branch_name>
$ db -lr <branch_name> // deletes local and remote with <branch_name>

这是到目前为止我得到的：

db () {
    declare opt
    declare OPTARG
    declare OPTIND

    has_l_option=false
    has_r_option=false

    while getopts :r:l: opt; do
        case $opt in
            r) has_r_option=true ;;
            l) has_l_option=true ;;
            :) echo "Missing argument for option -$OPTARG"; exit 1;;
           \?) echo "Unknown option -$OPTARG"; exit 1;;
        esac
    done

    shift $(( OPTIND - 1 ))

    if $has_l_option && $has_r_option; then
        git branch -d $1
        git push origin --delete $1
    elif $has_l_option; then
        git branch -d $1
    elif $has_r_option; then
        git push origin --delete $1
    else
        echo "Something went wrong"
    fi
}

我也很想抽象git分支-d和git push origin --delete调用其他函数以避免重复，但是我很难在bash中做到这一点：/

感谢您的帮助！

Answer 1

更新

# Takes -r or -l and a branch name
# and deletes the local and/or remote branch with that name
db () {
    declare opt
    declare OPTARG
    declare OPTIND

    BRANCH_NAME="$2"
    HAS_L_OPTION=false
    HAS_R_OPTION=false

    while getopts :rl opt; do
        case "$opt" in
            r) HAS_R_OPTION=true ;;
            l) HAS_L_OPTION=true ;;
            :) echo "Missing argument for option -$OPTARG"; return 1;;
           \?) echo "Unknown option -$OPTARG"; return 1;;
        esac
    done

    shift $(( OPTIND - 1 ))

    perform_branch_deletes_given "$BRANCH_NAME" "$HAS_L_OPTION" "$HAS_R_OPTION"

    echo "All done!"
}

# Helper
perform_branch_deletes_given () {
    BRANCH_NAME="$1"
    L="$2"
    R="$3"

    if "$L"; then
        git branch -D "$BRANCH_NAME"
    fi

    if "$R"; then
        git fetch -p origin  # prune local "cache" of remote branches
        echo "Local 'cache' of remote branches pruned"

        git push origin --delete "$BRANCH_NAME"
    fi
}

原始

好的，这是可行的：

db () {
    declare opt
    declare OPTARG
    declare OPTIND

    has_l_option=false
    has_r_option=false

    while getopts :rl opt; do
        case $opt in
            r) has_r_option=true ;;
            l) has_l_option=true ;;
            :) echo "Missing argument for option -$OPTARG"; exit 1;;
           \?) echo "Unknown option -$OPTARG"; exit 1;;
        esac
    done

    shift $(( OPTIND - 1 ))

    if $has_l_option; then
        git branch -d $1
    fi

    if $has_r_option; then
        git push origin --delete $1
    fi
}