Question

有人知道如何进行这项工作吗？（在python中）顺便说一句，我是初学者：）

import random
def roll():
    input1 = input("Player1, type 'ROLL' to roll.")
    if (input1 == "ROLL"):
        dice1 = random.randint(1,6)
        dice2 = random.randint(1,6)
        print("You rolled a " + dice1() + " and a " + dice2() ".")

    else:
        pass

roll()

我得到：

  File "main.py", line 9
    print("You rolled a " + dice1() + " and a " + dice2() ".")
                                                            ^
SyntaxError: invalid syntax

我还希望它重复“ Player1，键入'ROLL'滚动”。如果输入不等于ROLL 请:)谢谢

Answer 1

您附近的语法无效：

print("You rolled a " + dice1() + " and a " + dice2() ".")

使用string format：

替换：

print("You rolled a " + dice1() + " and a " + dice2() ".")

使用此：

print("You rolled a {} and {}".format(dice1,dice2))

注意：除非while loop与user-input匹配，否则您可以使用input继续服用ROLL：

因此：

import random

def roll():
    while True:
        input1 = input("Player1, type 'ROLL' to roll.")
        if input1 == "ROLL":
            dice1 = random.randint(1,6)
            dice2 = random.randint(1,6)
            print("You rolled a {} and {}".format(dice1, dice2))
            break  
roll()

输出：

Player1, type 'ROLL' to roll.whaaaat?
Player1, type 'ROLL' to roll.okay
Player1, type 'ROLL' to roll.roll
Player1, type 'ROLL' to roll.ROLL
You rolled a 2 and 2

Answer 2

typedef中存在语法错误。

两个print值都必须使用int强制转换为字符串。

str()和dice1不是函数，因此我们不能在它们旁边写上dice2。

()

应该是

print("You rolled a " + dice1() + " and a " + dice2() ".")

最好使用任何字符串附带的print("You rolled a " + str(dice1) + " and a " + str(dice2) + ".")函数。

format

Answer 3

整个功能应该是：

import random
def roll():
    input1 = input("Player1, type 'ROLL' to roll.")
    if (input1 == "ROLL"):
        dice1 = random.randint(1,6)
        dice2 = random.randint(1,6)
        print("You rolled a %s and a %s." % (dice1,dice2))

    else:
        pass

roll()

如果要显示两个变量dice1和dice2。

使用：

print("You rolled a %s and a %s." % (dice1,dice2))

代替：

print("You rolled a " + dice1() + " and a " + dice2() ".")

Answer 4

您在打印语句中忘记了逗号或+。您也将变量dice1 dice2称为函数。

import random

def roll():
    input1 = input("Player1, type 'ROLL' to roll. ")
    print(input1)
    if input1 == 'ROLL':
        dice1 = random.randint(1,6)
        dice2 = random.randint(1,6)
        print("You rolled a " + str(dice1) + " and a " + str(dice2) + ".")
    else:
        pass

roll()

Answer 5

Python的random.randint返回一个整数，因此您无需调用dice1和dice2变量。替换此行：

print("You rolled a " + dice1() + " and a " + dice2() ".")

与此：

print("You rolled a " + dice1 + " and a " + dice2 ".")

Python random module的参考

为什么我的打印语句会产生SyntaxError：无效的语法？

5 个答案: