文件夹“ a”中有各种名称的文本文件。我想阅读所有这些文本文件,并将字母“ b”添加到每个文本文件。我该怎么办?
willTransition(transition) {
if (this.controller.get('model.hasDirtyAttributes') && !confirm("Are you sure you want to abandon progress?")) {
transition.abort();
} else {
this.controller.get('model').rollbackAttributes();
}
}
答案 0 :(得分:1)
将数据追加到文件:
-首先:获取文件夹 a 中的所有文件。
-第二:使用 .txt 查找扩展名。
-第三:打开它并执行一些操作(“追加”或“重写”)。
演示:
import os
# your .txt files dir
path = 'a'
# append data what you want
appendData = 'b'
fileNames = list(os.walk(path))[0][2]
fileNames.sort(key=len)
fileNums = len(fileNames)
# your dst file extension
fileExt = '.txt'
# # Extract extension from filename
# fileExt = os.path.splitext(fileNames[0])[1]
for fileName in fileNames:
if fileName.endswith(fileExt):
fileFullPath = os.path.join(path, fileName)
with open(fileFullPath, 'a') as f:
f.write(appendData)
答案 1 :(得分:0)
就像其他人说的那样,这是一个简单的问题,可以在Google上轻松找到。无论如何,这是操作方法:
from os import listdir
from os.path import isfile, isdir, join
files = [file for file in listdir("files") if isfile(join("files", file))]
directories = [directory for directory in listdir("files") if isdir(join("files", directory))]
print(files)
for file_name in files:
try:
file = open("files/" + file_name, "a")
file.write("b")
file.close()
except IOError as err:
print("Could not open file because : ", err)
将“文件”替换为文件所在的目录或该目录的路径,例如“ directory0 / directory1 / directory_with_files”
答案 2 :(得分:0)
避免使用打开文件
f = open(input_dir, 'a')
f.close()
相反
with open(input_dir, 'a') as inputFile:
Do something
您还想要什么
import os
import glob # We will use this module to open only .txt files
path = 'your/path'
for filename in glob.glob(os.path.join(path, '*.txt'))
with open(filename, 'a') as inputFile:
inputFile.write('b')