我正在努力解决以下问题,并且似乎没有在线找到任何解决方案。
我在数据框上有一个for循环。该循环应该执行以下操作:如果列'reversal'== 1的内容,则在'action'列中填充1,跳过125行,在'action'的下一个第126行中填充-1,然后继续重复从下一行开始循环。如果列“ reversal”!= 1,则继续循环而不填充“ action”。
DateTime appointmentDate = DateTime.UtcNow;
DateTime appointmentDateToStore = new DateTime(
appointmentDate.Year,
appointmentDate.Month,
appointmentDate.Day,
appointmentDate.Hour,
appointmentDate.Minute,
0);
答案 0 :(得分:0)
import numpy as np
import pandas as pd
reversal=np.eye(126,dtype=int)
reversal=reversal.reshape(-1)
data=pd.DataFrame({"reverse":reversal})
data['action']=0
for index in range(len(data)):
if data.loc[index,"reverse"] == 1:
data.loc[index,'action'] = 1
if index<len(data.index)-126:
data.loc[index+126, 'action'] = -1
index= index + 127
您可以尝试
答案 1 :(得分:0)
如果可以使用索引,请不要使用itterrows()。
尝试一下:
#creating the on/off signal column
# df_zinc['action'] = 0
#
count = 0
# #creating the loop
for index in df_zinc.index:
if index < count:
continue
if df_zinc.at[index , 'reversal'] == 1:
df_zinc.at[index , 'action'] = 1
if index < len(df_zinc)-126: #the purpose of this condition is to not have the action column longer than the reversal column. Thuogh, it appears not to be working
df_zinc.at[index+126, 'action'] = -1
count = index + 127