Question

我想使用日期作为访问范围，但是当我写article.h3.span时，它给出了第一个范围（/）。如何访问带有日期的跨度？

 <a class="category-link" href="https://www.japantimes.co.jp/news_category/world/">
  World
 </a>
 <span>
  /
 </span>
 <a class="category-link" href="https://www.japantimes.co.jp/news_category/crime-legal-world/">
  Crime &amp; Legal
 </a>
 <span class="right date">
  Mar 19, 2019
 </span>
</h3>

下面是代码：

from bs4 import BeautifulSoup
ssl._create_default_https_context = ssl._create_unverified_context
article = "https://www.japantimes.co.jp/tag/cybersecurity/page/1/"
page = urllib.request.urlopen(article)
soup = BeautifulSoup(page, 'html.parser')
article = soup.find('article')
date = article.h3.span.text
print(date)

Answer 1

您可以使用next来获取日期，请参见下面的代码！

html = '''
 <a class="category-link" href="https://www.japantimes.co.jp/news_category/world/">
  World
 </a>
 <span>
  /
 </span>
 <a class="category-link" href="https://www.japantimes.co.jp/news_category/crime-legal-world/">
  Crime &amp; Legal
 </a>
 <span class="right date">
  Mar 19, 2019
 </span>
</h3>'''

soup = BeautifulSoup(html,'html.parser')
date = soup.find('span',attrs={'class':'right date'}).next
print(date.strip())

输出：

Mar 19, 2019

Answer 2

使用class=right date标签中的span可以做到：

from bs4 import BeautifulSoup

article = "https://www.japantimes.co.jp/tag/cybersecurity/page/1/"
page = urllib.request.urlopen(article)
soup = BeautifulSoup(page, 'html.parser')
date = soup.find('span', class_ ="right date")
print(date.text)

输出：

Mar 19, 2019

Answer 3

在该特定日期，您可以使用更快的单班课程选择器

item = soup.select_one('.date').text

如果全部想要

items = [item.text for item in soup.select('.date')]

如何在下面的代码中访问第二个跨度？

3 个答案: