我正在尝试合并两个表的数据,以便按状态获取总线索数。但是,由于某种原因,它要从table_1获得所有线索,并将其置于TX(Texas)下。两个查询在分开时可以正常工作,但与联合结合时不能正常工作。
TX 197 (This is the combined total of all leads in table_1)
CA 102 (This is the total for table_2. Does not include table_1)
TX 48 (This is the total for table_2. Does not include table_1)
FL 37 (This is the total for table_2. Does not include table_1)
MO 35 ...
NY 25 ...
etc. etc.
这是我的查询...
SELECT state, count(*) AS cnt FROM `table_1` WHERE submission_date > CURDATE() - INTERVAL 2 YEAR AND unk IS NULL
UNION ALL
SELECT state, count(*) AS cnt FROM `table_2` WHERE submission_date > CURDATE() - INTERVAL 2 YEAR AND unk IS NULL
GROUP BY state
ORDER BY cnt DESC
答案 0 :(得分:1)
我认为您需要一些括号,因此group by在联合之后执行,并将计数移出
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答案 1 :(得分:0)
GROUP BY
仅适用于 second 子查询。那不是你想要的。
在大多数数据库中,您的查询将生成错误。我想你想要
SELECT state, SUM(cnt) as cnt
FROM ((SELECT state, count(*) AS cnt
FROM `table_1`
WHERE submission_date > CURDATE() - INTERVAL 2 YEAR AND unk IS NULL
) UNION ALL
(SELECT state, count(*) AS cnt
FROM `table_2`
WHERE submission_date > CURDATE() - INTERVAL 2 YEAR AND unk IS NULL
GROUP BY state
)
) s
GROUP BY state
ORDER BY SUM(cnt) DESC;
在每个子查询中进行GROUP BY
是可选的。但是,GROUP BY
的性能增长比线性增长快。因此,即使有外部聚合,两个较小的GROUP BY
通常也比一个较大的<div class="row">
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要快。