这是我尝试过的。我认为当我创建apex测试控制器时,问题出在测试类中,我想将控制器的记录链接到我在测试类中创建的解决方案。
这是我在日志中发现的错误: “ common.apex.runtime.impl.ExecutionException:列表没有要分配给SObject的行” | 0x4888dd3c
apex class:
public with sharing class SolutionWrapper {
public ApexPages.StandardSetController controller;
public Opportunity opp{get; set;}
public Solutions__c oppId{get; set;}
public Solutions__c sol{get; set;}
public Solutions__c solution{get; set;}
public Account acc{get; set;}
public SolutionWrapper(ApexPages.StandardSetController controller) {
try{
solution = new Solutions__c();
solution = (Solutions__c)controller.getRecord();
if(solution.Id != null){
oppId = [SELECT id, Solutions__c.Opportunity__c
FROM Solutions__c
WHERE id =: solution.Id
LIMIT 1];
opp = [Select id,Name, AccountId, CurrencyIsoCode from
Opportunity where id =: oppId.Opportunity__c LIMIT:1];
}
if(opp.id !=null){
sol = [SELECT id,Name, Mail_Merge_Id__c,Solution_Country__c, Solutions__c.Opportunity__c
FROM Solutions__c
WHERE Solutions__c.Opportunity__c =: opp.id
LIMIT 1];
acc = [Select id,Name,Country__c from
Account where id=:opp.AccountId LIMIT: 1];
}
}
catch(Exception e){
ApexPages.addMessage(new ApexPages.message(ApexPages.Severity.ERROR,e.getMessage()));
}
}
}
这是我的考试班
顶点测试类:
@isTest
public class SolutionWrapperTest {
static testMethod void testMethodOpp(){
Account acc = new Account(Name='test', Country__c='test');
insert acc;
Opportunity opp = new Opportunity(Name='test', AccountId=acc.id, CurrencyIsoCode='GBP', StageName = 'Good',
CloseDate = date.today());
insert opp;
Solutions__c sol = new Solutions__c( Opportunity__c= opp.id, CurrencyIsoCode='GBP');
insert sol;
List<Solutions__c> listSol = new List<Solutions__c>();
listSol.add(sol);
PageReference pageRef = Page.NewVisualForcePage;
Test.setCurrentPage(pageRef);
Test.startTest();
ApexPages.StandardSetController stdController = new ApexPages.StandardSetController(listSol);
SolutionWrapper testSolution = new SolutionWrapper(stdController);
Test.stopTest();
}
}
答案 0 :(得分:0)
解决方案ID与我在测试类中插入的ID不同。我在类似Currency的字段上插入了一个虚拟值(即“ test”)。之后,我根据货币而不是ID从数据库中进行选择。