Question

我想在字符串中找到并替换与数组中任何字符串值匹配的任何单词。我可以使用 .contains（where ：

var playersApprovedArray = ["Monica","Zach","Chrissy"]
card.cardText = "Chrissy, do 10 jumping jacks right now!"

if playersApprovedArray.contains(where: card.cardText.contains) {

print("Found matching player in card text")

// Replace the matching word/player here with another word/player

}

但是我不知道如何用数组中的另一个字符串值替换匹配单词的出现。

Answer 1

这是一个简单的解决方案，可以将一个玩家替换为另一个玩家：

for i in playersApprovedArray.indices {
    let player = playersApprovedArray[i]
    if let range = cardText.range(of: player) {
        let otherIndex = (i + Int.random(in: 1..<playersApprovedArray.count)) % playersApprovedArray.count
        let otherPlayer = playersApprovedArray[otherIndex]
        cardText.replaceSubrange(range, with: otherPlayer)
        break
    }
}

如果句子中可能包含更多 players ，则可以删除break。

这是一个更快的解决方案，它将所有出现的任何玩家姓名都替换为另一个：

let playersApprovedArray = ["Monica","Zach","Chrissy"]
let cardText = " Chrissy, do 10 jumping jacks right now! "

var result = ""

var i = cardText.startIndex

while i < cardText.endIndex {
    var j = i
    while j < cardText.endIndex,
        CharacterSet.letters.inverted.isSuperset(of: CharacterSet(charactersIn: String(cardText[j])))
        {
        j = cardText.index(after: j)
    }

    var tempo1 = ""
    if i != j { tempo1 += cardText[i..<j] }

    if j < cardText.endIndex { i = j } else {
        result += tempo1
        break
    }

    while j < cardText.endIndex,
        CharacterSet.letters.isSuperset(of: CharacterSet(charactersIn: String(cardText[j])))
        {
        j = cardText.index(after: j)
    }

    let tempo2 = String(cardText[i..<j])

    if let index = playersApprovedArray.firstIndex(of: tempo2) {
        let otherIndex = (index + Int.random(in: 1..<playersApprovedArray.count)) % playersApprovedArray.count
        let otherPlayer = playersApprovedArray[otherIndex]
        result += tempo1 + otherPlayer
        //See comment below for possible early exit
    } else {
        result += tempo1 + tempo2
    }

    i = j
}

print(result)  // Monica, do 10 jumping jacks right now!

如果您确定字符串中只有一个 player ，那么您可以这样提前退出：

        ...
        result += tempo1 + otherPlayer + cardText[j...]
        break
        ...

如果字符串中的单词包含数组中的任何单词，如何替换该单词

1 个答案: