取消月份最高的输出月份

Question

我可以使用以下查询获取自2018年以来每个月被取消会员的数量-

SELECT DATEPART(YEAR, Cancel) [Year],
DATEPART(Month, Cancel) [Month], COUNT(1) [Count]
FROM Subscription
where DATEPART(YEAR, Cancel) >= 2018
GROUP BY DATEPART(year, Cancel),DATEPART(Month, Cancel)
ORDER BY 1,2

输出为

Year    Month    Count
2018    1        6416775
2018    2        458171
2018    3        29963575
2018    4        65393505

如何修改此查询，使其仅显示取消次数最多的月份？

更新

这是我想要的输出。每年应该输出最高的Count价值。

Year    Month    Count
2018    4        65393505
2019    2        458171

输出2018年第4个月是因为与前4个月相比，它具有最高的价值。

Answer 1

使用let array = ["one","two","three"] let string = "one two three four five six seven" 并通过order by count desc选择第一条记录，您将获得所需的输出：

top 1

Answer 2

使用row_number()

尝试以下操作

with cte as
(
SELECT DATEPART(YEAR, Cancel) [Year],
DATEPART(Month, Cancel) [Month], COUNT(1) [Count]
FROM Subscription
where DATEPART(YEAR, Cancel) >= 2018
GROUP BY DATEPART(year, Cancel),DATEPART(Month, Cancel)
ORDER BY 1,2
)
,cte1 as
( select *,ROW_NUMBER() OVER( partition by [Year] ORDER BY [Count] DESC) rn  from cte
) select * from cte1 where rn=1

Answer 3

正在关注

SELECT * FROM (SELECT DATEPART(YEAR, Cancel) [Year], DATEPART(Month, Cancel) [Month], COUNT(1) [Count] FROM Subscription WHERE DATEPART(YEAR, Cancel) >= 2018 GROUP BY DATEPART(year, Cancel),DATEPART(Month, Cancel) ORDER BY 1,2) as Table1 WHERE Count = (SELECT MAX COUNT(1) [Count] FROM Subscription WHERE DATEPART(YEAR, Cancel) >= 2018 GROUP BY DATEPART(year, Cancel),DATEPART(Month, Cancel) ORDER BY 1,2)