检索行之间特定列不同的行

时间：2019-03-19 17:47:30

标签： sql sql-server sql-server-2014 gaps-and-islands

我使用以下SQL来获取最高（最大）和第二高日期的行。在某些情况下，“旧行”和“新行”的唯一区别是生效日期。我只想按EMPLID显示旧行和新行，其中“旧”行和“新”行之间BANK_CD和/或ACCOUNT_NUM都不相同。

   WITH CTE AS ( 
 SELECT A.EMPLID 
 , C.VENDOR_ID
 , B.FIRST_NAME 
 , B.LAST_NAME 
 , A.BANK_CD 
 , A.ACCOUNT_NUM 
 , A.ACCOUNT_TYPE 
 , A.PRIORITY
 , A.LAST_UPDATE_DATE 
 , A.EFFDT 
 , MAX(A.LAST_UPDATE_DATE) OVER(PARTITION BY A.EMPLID) AS MAX_UPDATE_DATE 
 , ROW_NUMBER() OVER(PARTITION BY A.EMPLID 
  ORDER BY A.EFFDT DESC 
  , D.EFFDT DESC) AS RN 
  FROM PS_DIRECT_DEPOSIT D INNER JOIN PS_DIR_DEP_DISTRIB A ON A.EMPLID = D.EMPLID 
   AND A.EFFDT = D.EFFDT INNER JOIN PS_EMPLOYEES B ON B.EMPLID = A.EMPLID INNER JOIN PS_GHS_DIR_DEP_VND C ON C.EMPLID = A.EMPLID 
     INNER JOIN PS_DIR_DEP_DISTRIB E ON E.EMPLID = A.EMPLID AND E.EFFDT = A.EFFDT AND E.PRIORITY = A.PRIORITY 
 WHERE B.EMPL_STATUS NOT IN ('T','R','D') 
   AND ((A.DEPOSIT_TYPE = 'P' 
   AND A.AMOUNT_PCT = 100) 
    OR A.PRIORITY = 999 
    OR A.DEPOSIT_TYPE = 'B') 
   AND D.EFF_STATUS = 'A' )

 SELECT CASE WHEN RN = 1 THEN 'NEW ROW' WHEN RN = 2 THEN 'OLD ROW' END AS 
 'ROW_TYPE' , * 
 FROM CTE 
 WHERE RN IN (1, 2) 
 AND MAX_UPDATE_DATE >= GETDATE() - 8

这是我现在得到的输出示例：

ROW_TYPE    EMPLID     VENDOR_ID    FIRST_NAME    LAST_NAME    BANK_CD    ACCOUNT_NUM    ACCOUNT_TYPE    PRIORITY    LAST_UPDATE_DATE    EFFDT       MAX_UPDATE_DATE    RN
NEW ROW     12345      XYZ123       John          Smith        111111122  45678          C               999         03/12/2019          03/12/2019  03/12/2019         1
OLD ROW     12345      XYZ123       John          Smith        111111122  45678          C               999         10/25/2017          10/25/2017  10/25/2017         2
NEW ROW     47831      A86464       Samm          Bulle        754566654  98865          C               999         03/12/2019          06/08/2018  03/12/2019         1
OLD ROW     47831      A86464       Samm          Bulle        754566654  45678          C               999         10/25/2017          06/08/2018  10/25/2017         2
NEW ROW     32456      KG4561       Kilo          Renne        875123311  32146          C               300         09/02/2018          09/02/2018  09/02/2018         1
OLD ROW     32456      KG4561       Kilo          Renne        971215477  78131          C               310         12/21/2017          12/21/2017  12/21/2017         2

在上面的示例中，我不想输出前两组EMPLID行（前4行），因为它们在新行和旧行之间具有相同的BANK_CD和ACCOUNT_NUM。我想保留在输出中的最后一组行，因为您可以看到BANK_CD和ACCOUNT_NUM是不同的（虽然可能包括在内）。

我尝试为PS_DIR_DEP_DISTRIB添加一个自联接，然后在WHERE子句中添加AND（A.BANK_CD <> E.BANK_CD或A.ACCOUNT_NUM <> E.ACCOUNT_NUM），如下所示：

   WITH CTE AS ( 
 SELECT A.EMPLID 
 --, C.VENDOR_ID
 , B.FIRST_NAME 
 , B.LAST_NAME 
 , A.BANK_CD 
 , A.ACCOUNT_NUM 
 , A.ACCOUNT_TYPE 
 , A.PRIORITY
 , A.LAST_UPDATE_DATE 
 , A.EFFDT 
 , MAX(A.LAST_UPDATE_DATE) OVER(PARTITION BY A.EMPLID) AS MAX_UPDATE_DATE 
 , ROW_NUMBER() OVER(PARTITION BY A.EMPLID 
  ORDER BY A.EFFDT DESC 
  , D.EFFDT DESC) AS RN 
  FROM PS_DIRECT_DEPOSIT D INNER JOIN PS_DIR_DEP_DISTRIB A ON A.EMPLID = D.EMPLID 
   AND A.EFFDT = D.EFFDT INNER JOIN PS_EMPLOYEES B ON B.EMPLID = A.EMPLID INNER JOIN PS_GHS_DIR_DEP_VND C ON C.EMPLID = A.EMPLID 
 ---ADDING SELF JOIN BELOW---
     INNER JOIN PS_DIR_DEP_DISTRIB E ON E.EMPLID = A.EMPLID AND E.EFFDT = 
     A.EFFDT AND E.PRIORITY = A.PRIORITY 
 WHERE B.EMPL_STATUS NOT IN ('T','R','D') 
   AND ((A.DEPOSIT_TYPE = 'P' 
   AND A.AMOUNT_PCT = 100) 
    OR A.PRIORITY = 999 
    OR A.DEPOSIT_TYPE = 'B') 
   AND D.EFF_STATUS = 'A' 
---ADDING NEW WHERE CONDITION BELOW---
   AND (E.ACCOUNT_NUM <> A.ACCOUNT_NUM OR E.BANK_CD <> A.BANK_CD )) 
 SELECT CASE WHEN RN = 1 THEN 'NEW ROW' WHEN RN = 2 THEN 'OLD ROW' END AS 'ROW_TYPE' 
 , * 
  FROM CTE 
  WHERE RN IN (1, 2) 
  AND MAX_UPDATE_DATE >= GETDATE() - 8

但是，当我进行上述更改时，我根本没有返回任何数据。我在做什么错了？

19/3/20编辑：

在下面的塔雷克（Tarek）建议的答案之后，我似乎缺少了一些我希望最终输出中的行。看来，添加的BANK_CD_prev和ACCOUNT_NUM_prev的新字段在我希望它们显示的行中返回NULL的值，因此为什么最终查询没有检索到它们。该如何处理？

ROW_TYPE    EMPLID    FIRST_NAME    LAST_NAME   BANK_CD       ACCOUNT_NUM     ACCOUNT_TYPE  PRIORITY    LAST_UPDATE_DATE       EFFDT        MAX_UPDATE_DATE  RN    BANK_CD_prev   ACCOUNT_NUM_prev  
NEW ROW     56789     Test          User        874556411     54765           C             999         2019-02-28             2019-02-28   2019-02-28       1     NULL           NULL
OLD ROW     56789     Test          User        874556411     98451           C             999         2017-10-09             2017-10-09   2017-10-09       1     874556411      54765
NEW ROW     56789     Sampl         Test        756561623     46331           C             999         2018-03-12             2018-03-12   2018-03-12       1     NULL           NULL
OLD ROW     56789     Test          User        756561623     46331           C             999         2015-05-18             2015-05-18   2015-05-18       1     756561623      46331

请注意，上面的查询在而不的条件下运行（AND BANK_CD <> BANK_CD_prev AND ACCOUNT_NUM <> ACCOUNT_NUM_prev只是为了让我知道为什么我缺少一些行。在这种情况下，您可以看到第一个{ {1}}的两行ACCOUNT_NUM不同，因此我应该同时输出两行。第二个EMPLID（最后两行）的区别在于EMPLID和{{1 }}对于两行都是相同的，因此我不希望输出该输出（不是这样，这是正确的），但是仍然像第一组行中一样显示BANK_CD。 / p>

19/3/20编辑2：您可以看到ACCOUNT_NUM和NULL中有一些奇怪的数字，我认为这是一个问题。 

BANK_CD_COUNT

此链接包含“创建表”和“插入”脚本，供任何可以帮助复制此脚本的人使用。

https://pastebin.com/cZLhMmet

2 个答案:

答案 0 :(得分：3)

一种实现方法是使用LEAD和LAG函数。我们在这里都需要。

这是您的原始查询，该查询已按日期格式化并注释掉了过滤器。

WITH 
CTE
AS 
(
    SELECT
        A.EMPLID
        ,C.VENDOR_ID
        ,B.FIRST_NAME
        ,B.LAST_NAME
        ,A.BANK_CD
        ,A.ACCOUNT_NUM
        ,A.ACCOUNT_TYPE
        ,A.PRIORITY
        ,A.LAST_UPDATE_DATE
        ,A.EFFDT
        ,MAX(A.LAST_UPDATE_DATE) OVER (PARTITION BY A.EMPLID) AS MAX_UPDATE_DATE
        ,ROW_NUMBER() OVER (PARTITION BY A.EMPLID ORDER BY A.EFFDT DESC, D.EFFDT DESC) AS RN
    FROM 
        PS_DIRECT_DEPOSIT D
        INNER JOIN PS_DIR_DEP_DISTRIB A 
            ON A.EMPLID = D.EMPLID
            AND A.EFFDT = D.EFFDT
        INNER JOIN PS_EMPLOYEES B ON B.EMPLID = A.EMPLID
        INNER JOIN PS_GHS_DIR_DEP_VND C ON C.EMPLID = A.EMPLID
        INNER JOIN PS_DIR_DEP_DISTRIB E 
            ON E.EMPLID = A.EMPLID
            AND E.EFFDT = A.EFFDT
            AND E.PRIORITY = A.PRIORITY
    WHERE 
        B.EMPL_STATUS NOT IN ('T','R','D')
        AND 
        (
            (
                A.DEPOSIT_TYPE = 'P'
                AND A.AMOUNT_PCT = 100
            )
            OR A.PRIORITY = 999
            OR A.DEPOSIT_TYPE = 'B'
        )
        AND D.EFF_STATUS = 'A'
)
SELECT 
    CASE 
        WHEN RN = 1 THEN 'NEW ROW'
        WHEN RN = 2 THEN 'OLD ROW'
    END AS 'ROW_TYPE'
    ,*
FROM CTE
WHERE 
    RN IN (1,2)
    --AND MAX_UPDATE_DATE >= GETDATE() - 8
;

此查询根据您的示例数据返回以下结果：

+----------+---------+-----------+------------+-----------+----------+-------------+--------------+----------+-------------------------+-------------------------+-------------------------+----+
| ROW_TYPE | EMPLID  | VENDOR_ID | FIRST_NAME | LAST_NAME | BANK_CD  | ACCOUNT_NUM | ACCOUNT_TYPE | PRIORITY |    LAST_UPDATE_DATE     |          EFFDT          |     MAX_UPDATE_DATE     | RN |
+----------+---------+-----------+------------+-----------+----------+-------------+--------------+----------+-------------------------+-------------------------+-------------------------+----+
| NEW ROW  |  097432 | 3471B     | H          | Adam      | 09146115 |    13404891 | C            |      999 | 2016-06-10 00:00:00.000 | 2016-06-10 00:00:00.000 | 2016-06-10 00:00:00.000 |  1 |
| OLD ROW  |  097432 | 3471B     | H          | Adam      | 09146115 |    13404891 | C            |      999 | 2016-06-10 00:00:00.000 | 2014-11-05 00:00:00.000 | 2016-06-10 00:00:00.000 |  2 |
| NEW ROW  |  100765 | 1272B     | V          | Milo      |  2358414 |      040925 | S            |      310 | 2014-03-05 00:00:00.000 | 2011-04-27 00:00:00.000 | 2014-03-05 00:00:00.000 |  1 |
| OLD ROW  |  100765 | 1272B     | V          | Milo      |  2358414 |      040925 | S            |      300 | 2014-03-05 00:00:00.000 | 2001-08-23 00:00:00.000 | 2014-03-05 00:00:00.000 |  2 |
| NEW ROW  | 1045632 | 3870A     | V          | Olo       |  2345794 |   179410860 | C            |      999 | 2018-08-16 00:00:00.000 | 2018-08-16 00:00:00.000 | 2018-08-16 00:00:00.000 |  1 |
| OLD ROW  | 1045632 | 3870A     | V          | Olo       |  2345794 |   179410860 | C            |      310 | 2011-02-25 00:00:00.000 | 2011-02-25 00:00:00.000 | 2018-08-16 00:00:00.000 |  2 |
| NEW ROW  |   21345 | 12345A    | J          | Smith     |  0224547 |    59167824 | C            |      999 | 2019-02-28 00:00:00.000 | 2019-02-28 00:00:00.000 | 2019-02-28 00:00:00.000 |  1 |
| OLD ROW  |   21345 | 12345A    | J          | Smith     |  0224547 |      591678 | C            |      999 | 2017-11-08 00:00:00.000 | 2017-10-17 00:00:00.000 | 2019-02-28 00:00:00.000 |  2 |
| NEW ROW  |   26110 | 1272B     | S          | Sams      |  8208302 |      822328 | C            |      999 | 2019-02-08 00:00:00.000 | 2019-02-08 00:00:00.000 | 2019-02-08 00:00:00.000 |  1 |
| OLD ROW  |   26110 | 1272B     | S          | Sams      |  8208302 |      822328 | C            |      315 | 2014-03-05 00:00:00.000 | 2012-07-30 00:00:00.000 | 2019-02-08 00:00:00.000 |  2 |
+----------+---------+-----------+------------+-----------+----------+-------------+--------------+----------+-------------------------+-------------------------+-------------------------+----+

我在这里包括了它，所以您可以看到与下面的区别。

这是在LEAD子句中添加了额外过滤器的新查询，其中添加了LAG和WHERE函数（我们都需要获取上一行和下一行）。

LEAD和LAG到达窗口末尾时将返回NULL。例如，LAG（上一个值）将对窗口的第一行返回NULL，因为还没有“上一个”行。

因此，对于第一行（rn = 1），我们需要将其值与“ next”进行比较。

对于第二行（rn = 2），我们需要将其值与“上一个”进行比较。

最终查询 

WITH 
CTE
AS 
(
    SELECT
        A.EMPLID
        ,C.VENDOR_ID
        ,B.FIRST_NAME
        ,B.LAST_NAME
        ,A.BANK_CD
        ,A.ACCOUNT_NUM
        ,A.ACCOUNT_TYPE
        ,A.PRIORITY
        ,A.LAST_UPDATE_DATE
        ,A.EFFDT
        ,MAX(A.LAST_UPDATE_DATE) OVER (PARTITION BY A.EMPLID) AS MAX_UPDATE_DATE
        ,ROW_NUMBER() OVER (PARTITION BY A.EMPLID ORDER BY A.EFFDT DESC, D.EFFDT DESC) AS RN

        ,LAG(A.BANK_CD) OVER (PARTITION BY A.EMPLID ORDER BY A.EFFDT DESC, D.EFFDT DESC) AS BANK_CD_prev
        ,LEAD(A.BANK_CD) OVER (PARTITION BY A.EMPLID ORDER BY A.EFFDT DESC, D.EFFDT DESC) AS BANK_CD_next
        ,LAG(A.ACCOUNT_NUM) OVER (PARTITION BY A.EMPLID ORDER BY A.EFFDT DESC, D.EFFDT DESC) AS ACCOUNT_NUM_prev
        ,LEAD(A.ACCOUNT_NUM) OVER (PARTITION BY A.EMPLID ORDER BY A.EFFDT DESC, D.EFFDT DESC) AS ACCOUNT_NUM_next
    FROM 
        PS_DIRECT_DEPOSIT D
        INNER JOIN PS_DIR_DEP_DISTRIB A 
            ON A.EMPLID = D.EMPLID
            AND A.EFFDT = D.EFFDT
        INNER JOIN PS_EMPLOYEES B ON B.EMPLID = A.EMPLID
        INNER JOIN PS_GHS_DIR_DEP_VND C ON C.EMPLID = A.EMPLID
        INNER JOIN PS_DIR_DEP_DISTRIB E 
            ON E.EMPLID = A.EMPLID
            AND E.EFFDT = A.EFFDT
            AND E.PRIORITY = A.PRIORITY
    WHERE 
        B.EMPL_STATUS NOT IN ('T','R','D')
        AND 
        (
            (
                A.DEPOSIT_TYPE = 'P'
                AND A.AMOUNT_PCT = 100
            )
            OR A.PRIORITY = 999
            OR A.DEPOSIT_TYPE = 'B'
        )
        AND D.EFF_STATUS = 'A'
)
SELECT 
    CASE 
        WHEN RN = 1 THEN 'NEW ROW'
        WHEN RN = 2 THEN 'OLD ROW'
    END AS 'ROW_TYPE'
    ,*
FROM CTE
WHERE 
    RN IN (1,2)
    AND 
    (
        (
            rn = 1
            AND BANK_CD <> BANK_CD_next
        )
        OR
        (
            rn = 1
            AND ACCOUNT_NUM <> ACCOUNT_NUM_next
        )

        OR

        (
            rn = 2
            AND BANK_CD <> BANK_CD_prev
        )
        OR
        (
            rn = 2
            AND ACCOUNT_NUM <> ACCOUNT_NUM_prev
        )
    )
    --AND MAX_UPDATE_DATE >= GETDATE() - 8
;

最终结果 

+----------+--------+-----------+------------+-----------+---------+-------------+--------------+----------+-------------------------+-------------------------+-------------------------+----+--------------+--------------+------------------+------------------+
| ROW_TYPE | EMPLID | VENDOR_ID | FIRST_NAME | LAST_NAME | BANK_CD | ACCOUNT_NUM | ACCOUNT_TYPE | PRIORITY |    LAST_UPDATE_DATE     |          EFFDT          |     MAX_UPDATE_DATE     | RN | BANK_CD_prev | BANK_CD_next | ACCOUNT_NUM_prev | ACCOUNT_NUM_next |
+----------+--------+-----------+------------+-----------+---------+-------------+--------------+----------+-------------------------+-------------------------+-------------------------+----+--------------+--------------+------------------+------------------+
| NEW ROW  |  21345 | 12345A    | J          | Smith     | 0224547 |    59167824 | C            |      999 | 2019-02-28 00:00:00.000 | 2019-02-28 00:00:00.000 | 2019-02-28 00:00:00.000 |  1 | NULL         | 0224547      | NULL             | 591678           |
| OLD ROW  |  21345 | 12345A    | J          | Smith     | 0224547 |      591678 | C            |      999 | 2017-11-08 00:00:00.000 | 2017-10-17 00:00:00.000 | 2019-02-28 00:00:00.000 |  2 | 0224547      | NULL         | 59167824         | NULL             |
+----------+--------+-----------+------------+-----------+---------+-------------+--------------+----------+-------------------------+-------------------------+-------------------------+----+--------------+--------------+------------------+------------------+

答案 1 :(得分：0)

我只需将以下分析功能添加到您的CTE中，以返回前身：

LAG(A.BANK_CD) OVER (PARTITION BY A.EMPLID ORDER BY A.EFFDT DESC) AS BANK_CD_prev,
LAG(A.ACCOUNT_NUM) OVER (PARTITION BY A.EMPLID ORDER BY A.EFFDT DESC) AS ACCOUNT_NUM_prev

然后，您只需要在主查询中引用它，就可以完成

FROM CTE 
WHERE RN IN (1, 2) 
AND MAX_UPDATE_DATE >= GETDATE() - 8
AND BANK_CD <> BANK_CD_prev
AND ACCOUNT_NUM <> ACCOUNT_NUM_prev

如果可以解决您的问题，请回复。由于您没有提供示例进行测试，所以很难说。

编辑：我的意思是：将该解决方案与您的初始方法一起使用，而根本不需要自我加入。它不会帮助您解决问题。

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