Question

尝试执行以下命令时遇到了麻烦

我有一张表格，上面有病人的出入记录

My_table

ID     NAME       DATE       TYPE   PERFORMANCE_SCORE  
103    John       08/12/18    EX      8
103    John       08/04/18    EN      5
105    Dave       06/22/18    EX      12
105    Dave       06/14/18    EN      16
108    Ben        02/07/19    EX      15
108    Ben        02/01/19    EN      19

其中EN =进入记录，EX =离开记录。我需要获取进入和退出记录，其中“退出记录（EX）”和“进入记录（EN）”之间的“ Performance_Score”差异为负。我希望最终结果会像

必填结果：

ID     NAME       DATE       TYPE   PERFORMANCE_SCORE  
105    Dave       06/22/18    EX      12
105    Dave       06/14/18    EN      16
108    Ben        02/07/19    EX      15
108    Ben        02/01/19    EN      19

我试图像下面这样用Union来实现

select * from
(
SELECT
        a.ID,
        a.NAME,
        a.DATE,
        a.TYPE,
        a.PERFORMANCE_SCORE  
    FROM My_table a
    WHERE
        a.TYPE = 'EX' 

UNION ALL

    SELECT
        b.ID,
        b.NAME,
        b.DATE,
        b.TYPE,
        b.PERFORMANCE_SCORE  
    FROM My_table b
    WHERE
        b.TYPE = 'EN'
)
where a.ID = b.ID and a.NAME = b.NAME and b.PERFORMANCE_SCORE - a.PERFORMANCE_SCORE < 0  --> I know this condition can't be used outside the UNION block, but how can I implement this condition to get the result I need?

当我尝试像这样使用INNER JOIN

SELECT * FROM
(
    SELECT
        ID,
        NAME,
        DATE,
        TYPE,
        PERFORMANCE_SCORE
    FROM My_table
    WHERE
        TYPE = 'EX' 
)
a
INNER JOIN
(
    SELECT
        ID,
        NAME,
        DATE,
        TYPE,
        PERFORMANCE_SCORE
    FROM My_table
    WHERE
        TYPE = 'EN'
)
b
ON
    a.ID = b.ID AND a.NAME = b.NAME and b.PERFORMANCE_SCORE - a.PERFORMANCE_SCORE < 0

我得到了我需要的记录，但是它们都像下面一样排成一排

ID     NAME       DATE       TYPE   PERFORMANCE_SCORE  ID     NAME       DATE       TYPE   PERFORMANCE_SCORE
105    Dave       06/22/18    EX      12               105    Dave       06/14/18    EN      16   
108    Ben        02/07/19    EX      15               108    Ben        02/01/19    EN      19

我想念什么？

Answer 1

具有EXISTS：

select t.* from my_table t
where exists (
  select 1 from my_table
  where
  name = t.name
  and 
  type = case when t.type = 'EX' then 'EN' else 'EX' end
  and
  (performance_score - t.performance_score) * (case when t.type = 'EX' then 1 else -1 end) > 0
)

Answer 2

我在考虑窗口功能：

select t.*
from (select t.*,
             sum(case when t.type = 'EX' then t.performance_score
                      when t.type = 'EN' then -t.performance_score
                 end) as diff_performance
      from my_table t
      where t.type in ('EX', 'EN')
     ) t
where diff_performance < 0;

如何在同一表上选择具有相同ID和名称的两个匹配记录

2 个答案: