PDO准备的更新语句以某种方式更新表中所选记录的datetime列,即使该特定的datetime列甚至不在查询中。
if(isset($_POST['editCriteria']))
{
$value = $_POST['editCriteria'];
$editusername = $value['editusername'];
$hiddenUsername = $value['hiddenUsername'];
$editfullname = $value['editfullname'];
$editemail = $value['editemail'];
$edituserlevel = $value['edituserlevel'];
$editdivision = $value['editdivision'];
$editdept = $value['editdept'];
$editphone = $value['editphone'];
try
{
$dbc->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$update = $dbc->prepare("UPDATE users_edi SET username = :uname,
fullname = :fname, userlevel = :ulevel, email = :uemail,
division = :udivision, dept = :udept, phone = :uphone WHERE username = :hname");
$update->execute([
'uname' => $editusername,
'fname' => $editfullname,
'ulevel' => $edituserlevel,
'uemail' => $editemail,
'udivision' => $editdivision,
'udept' => $editdept,
'uphone' => $editphone,
'hname' => $hiddenUsername
]);
if($update)
{
echo "Success: User has been updated.";
}
}
catch(PDOException $e)
{
echo "Error: " . $e->getMessage();
}
}
在数据库表中,有一个名为lastLoginDate的列正在更新为当前日期时间。
如果您在上面的更新语句中注意到,则该查询不包含lastLoginDate。
lastLoginDate甚至不在查询中时如何更新?
答案 0 :(得分:0)
使用SHOW CREATE TABLE命令后,lastLoginDate列确实存在触发器。
CREATE TABLE `users_edi` (
`username` varchar(30) NOT NULL DEFAULT '',
`fullname` varchar(50) DEFAULT NULL,
`userlevel` tinyint(1) unsigned NOT NULL,
`ipaddress` varchar(30) DEFAULT NULL,
`email` varchar(150) DEFAULT NULL,
`entrydate` datetime DEFAULT NULL,
`division` varchar(35) DEFAULT NULL,
`password` varchar(32) DEFAULT NULL,
`userid` varchar(32) DEFAULT NULL,
`timestamp` int(11) unsigned NOT NULL,
`job_title` varchar(30) DEFAULT NULL,
`dept` varchar(50) DEFAULT NULL,
`phone` varchar(11) DEFAULT NULL,
`lastLoginDate` datetime DEFAULT NULL ON UPDATE CURRENT_TIMESTAMP, // <-- here
PRIMARY KEY (`username`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8
我将不得不问另一个有关如何删除此触发器的问题。