Question

我正在将reduxsauce库用于redux存储，并且想对其中的单个redux存储进行单元测试。 redux文件：

import { createReducer, createActions } from 'reduxsauce'
import Immutable from 'seamless-immutable'

/* ------------- Types and Action Creators ------------- */

const { Types, Creators } = createActions({
  getLanguage: [],
  setLanguage: ['language']
})

export const LanguageTypes = Types
export default Creators

/* ------------- Initial State ------------- */

export const INITIAL_STATE = Immutable({
  language: "en"
})

/* ------------- Reducers ------------- */


export const getLanguage = (state: Object, {}: Object) => {
    return state.merge({})
}

export const setLanguage = (state: Object, { language }: Object) => {
    return state.merge({ language })
}

/* ------------- Hookup Reducers To Types ------------- */

export const reducer = createReducer(INITIAL_STATE, {
  [Types.SET_LANGUAGE]: setLanguage,
  [Types.GET_LANGUAGE]: getLanguage,
})

测试：

import * as actions from '../../../redux/LanguageRedux'
import * as types from '../../../redux/LanguageRedux'

describe('Language redux ', () => {
  it('should have default language ', () => {
    expect(actions.INITIAL_STATE.language).toEqual("en")
  }),
  it('should be able to set the language', () => {
    // I know the calls below are not tests but still its relevant with the error
    actions.getLanguage()
    actions.setLanguage()
  })
})

错误：

● Language redux  › should be able to set the language

    TypeError: Cannot destructure 'undefined' or 'null'.

      21 |
      22 |
    > 23 | export const getLanguage = (state: Object, {}: Object) => {
         |                            ^
      24 |     return state.merge({})
      25 | }
      26 |

      at Object.getLanguage (src/redux/LanguageRedux.js:23:28)
      at Object.getLanguage (src/__tests__/src/redux/LanguageRedux.js:9:13)

现在，我在另一个文件中配置了存储，但是reducer被合并在另一个文件中：

import { combineReducers } from 'redux'
import configureStore from './CreateStore'

import rootSaga from '../sagas'

export default () => {
    /* ------------- Assemble The Reducers ------------- */
    const rootReducer = combineReducers({
        language: require('./LanguageRedux').reducer
    })

    return configureStore(rootReducer, rootSaga)
}

任何人都有关于如何测试redux动作等的线索。使用正常的redux我可以找到很多文章，但是使用reduxsauce库，我似乎什么也找不到。有什么线索吗？

Answer 1

正在测试什么

LanguageRedux.js具有以下导出：

LanguageTypes-动作类型的映射
Creators-动作创建者的地图
INITIAL_STATE-应用的初始状态
getLanguage和setLanguage-减速器功能
reducer-redux减速器

我建议导入具有预期标识符的所有内容，如下所示：

import Creators, {
  LanguageTypes,
  INITIAL_STATE,
  getLanguage,
  setLanguage,
  reducer
 } from '../../../redux/LanguageRedux';

注意：看来getLanguage动作是不必要的，因为它对状态没有任何作用（如果应用获取的语言是它应该从状态中读取的内容），但是我会把它留在那里，因为它在问题代码中。

LanguageTypes

LanguageTypes只是动作类型与其关联的字符串值的映射：

it('should export the expected action types', () => {
  expect(LanguageTypes).toEqual({
    GET_LANGUAGE: 'GET_LANGUAGE',
    SET_LANGUAGE: 'SET_LANGUAGE'
  });  // Success!
});

创作者

Creators是动作创建者的地图。

每个动作创建者都是一个纯函数，可以根据给定的参数生成一个动作对象：

describe('Creators', () => {

  describe('getLanguage', () => {

    it('should return the expected action', () => {
      expect(Creators.getLanguage()).toEqual({
        type: LanguageTypes.GET_LANGUAGE
      });
    });

    it('should ignore extra args', () => {
      expect(Creators.getLanguage('extra arg')).toEqual({
        type: LanguageTypes.GET_LANGUAGE
      });
    });

  });

  describe('setLanguage', () => {

    it('should return the expected action when passed nothing', () => {
      expect(Creators.setLanguage()).toEqual({
        type: LanguageTypes.SET_LANGUAGE
      });  // Success!
    });

    it('should return the expected action when passed a language', () => {
      expect(Creators.setLanguage('en')).toEqual({
        type: LanguageTypes.SET_LANGUAGE,
        language: 'en'
      });  // Success!
    });

    it('should ignore extra args', () => {
      expect(Creators.setLanguage('es', 'extra arg')).toEqual({
        type: LanguageTypes.SET_LANGUAGE,
        language: 'es'
      });  // Success!
    });

  });

});

INITIAL_STATE

INITIAL_STATE只是应用程序开始的初始状态对象：

it('should set the initial state ', () => {
  expect(INITIAL_STATE).toEqual({ language: "en" });  // Success!
});

减速器功能

getLanguage和setLanguage是化简函数，这意味着它们是纯函数，它们基于给定的现有状态和操作返回新状态：

describe('reducers', () => {

  describe('getLanguage', () => {

    it('should do nothing (probably should not be an action)', () => {
      expect(getLanguage(INITIAL_STATE, {})).toEqual(INITIAL_STATE);  // Success!
    });

    it('should ignore extra args', () => {
      expect(getLanguage(INITIAL_STATE, { extra: 'arg' })).toEqual(INITIAL_STATE);  // Success!
    });

  });

  describe('setLanguage', () => {

    it('should set the language', () => {
      expect(setLanguage(INITIAL_STATE, { language: 'es' })).toEqual({
        language: 'es'
      });  // Success!
    });

    it('should ignore extra args', () => {
      expect(setLanguage(INITIAL_STATE, { language: 'fr', extra: 'arg' })).toEqual({
        language: 'fr'
      });  // Success!
    });

  });

});

请注意，使用reduxsauce测试化简功能要比测试标准redux化简更加容易，因为将仅调用它们旨在处理的动作。

减速器

reducer是redux reducer，其工作是将动作路由到相应的reducer函数并返回结果状态：

describe('reducer', () => {

  it('should return initial state if passed nothing', () => {
    expect(reducer()).toEqual(INITIAL_STATE);  // Success!
  });

  it('should route GET_LANGUAGE to getLanguage', () => {
    expect(reducer(INITIAL_STATE, Creators.getLanguage())).toEqual(INITIAL_STATE);  // Success!
  });

  it('should route SET_LANGUAGE to setLanguage', () => {
    expect(reducer(Immutable({ language: 'es' }), Creators.setLanguage('fr'))).toEqual({
      language: 'fr'
    });  // Success!
  });

});

注意：可以通过多种方法测试reducer。上面的方法通过化简器功能一直传递状态和动作。它很彻底，但是与上面的reducer功能测试有很多重叠。

最基本的选择是监视createReducer并只需验证它是否已与预期的INITIAL_STATE和映射对象一起被调用。

与上述完整方法中间的方法是模拟化简函数，传递reducer各种动作，并验证是否调用了正确的化简函数。这可能是理想的方法，但是由于createReducer会在导入代码并捕获对本地函数{{1的引用后立即运行}}和setLanguage。如果您想使用这种方法，那么最简单的方法是将getLanguage移到其自己的模块中，这样您就可以在将reducer导入到您的计算机中的之前对reducer函数进行模拟。测试代码。

如何对Reduxsauce进行单元测试？

1 个答案:

正在测试什么

LanguageTypes

创作者

INITIAL_STATE

减速器功能

减速器