当我尝试向代码中添加注释时,我发现了一个奇怪的问题。我使用三引号引起来的字符串进行注释,但是程序由于出现以下错误而崩溃:
IndentationError: unexpected indent
当我使用#
注释三引号的字符串时,一切正常。有人知道这个错误的原因以及如何解决吗?
我的代码:
#This programs show that comments using # rather than """ """
def main():
print("let's do something")
#Try using hashtag to comment this block to get code working
'''
Note following block gives you a non-sense indent error
The next step would be to consider how to get all the words from spam and ham
folder from different directory. My suggestion would be do it twice and then
concentrate two lists
Frist think about the most efficient way
For example, we might need to get rid off the duplicated words in the beginning
The thoughts of writing the algorithem to create the dictionary
Method-1:
1. To append all the list from the email all-together
2. Eliminate those duplicated words
cons: the list might become super large
I Choose method-2 to save the memory
Method-2:
1. kill the duplicated words in each string
2. Only append elements that is not already in the dictionary
Note:
1. In this case, the length of feature actually was determined by the
training cohorts, as we used the different English terms to decide feature
cons: the process time might be super long
'''
def wtf_python(var1, var2):
var3 = var1 + var2 + (var1*var2)
return var3
wtfRst1 = wtf_python(1,2)
wtfRst2 = wtf_python(3,4)
rstAll = { "wtfRst1" : wtfRst1,
"wtfRst2" : wtfRst2
}
return(rstAll)
if __name__ == "__main__":
mainRst = main()
print("wtfRst1 is :\n", mainRst['wtfRst1'])
print("wtfRst2 is :\n", mainRst['wtfRst2'])
答案 0 :(得分:1)
您应该将三引号字符串的缩进级别向右推一个标签。
尽管三引号字符串通常用作注释,但是它们是普通的python表达式,因此它们应遵循该语言的语法。
答案 1 :(得分:1)
罪魁祸首:
在函数定义内移动注释:
原因:
由于三引号字符串是有效的python exp,因此应该对它们进行同样的对待,即在函数作用域之内。
因此:
def main():
print("let's do something")
#Try using hashtag to comment this block to get code working
'''
Note following block gives you a non-sense indent error
The next step would be to consider how to get all the words from spam and ham
folder from different directory. My suggestion would be do it twice and then
concentrate two lists
Frist think about the most efficient way
For example, we might need to get rid off the duplicated words in the beginning
The thoughts of writing the algorithem to create the dictionary
Method-1:
1. To append all the list from the email all-together
2. Eliminate those duplicated words
cons: the list might become super large
I Choose method-2 to save the memory
Method-2:
1. kill the duplicated words in each string
2. Only append elements that is not already in the dictionary
Note:
1. In this case, the length of feature actually was determined by the
training cohorts, as we used the different English terms to decide feature
cons: the process time might be super long
'''
def wtf_python(var1, var2):
var3 = var1 + var2 + (var1*var2)
return var3
wtfRst1 = wtf_python(1,2)
wtfRst2 = wtf_python(3,4)
rstAll = { "wtfRst1" : wtfRst1,
"wtfRst2" : wtfRst2
}
return(rstAll)
if __name__ == "__main__":
mainRst = main()
print("wtfRst1 is :\n", mainRst['wtfRst1'])
print("wtfRst2 is :\n", mainRst['wtfRst2'])
输出:
let's do something
wtfRst1 is :
5
wtfRst2 is :
19
答案 2 :(得分:1)
用三引号引起来的字符串作为注释必须是有效的Python字符串。有效的Python字符串必须正确缩进。
Python会看到多行字符串,然后对其求值,但是由于您没有为其分配变量,因此该字符串会在下一行被丢弃。