Question

我已经通过PHP和PDO创建了SQLite3数据库
插入记录和删除记录可以正常工作，但UPDATE记录不能

public function update_All($mStore_Order_DataClass) {
            try 
            {
                $sql = "UPDATE Orders "
                        . "SET x_Name = :x_Name, "
                        . "x_PhoneNumber1 = :x_PhoneNumber1, "
                        . "x_PhoneNumber2 = :x_PhoneNumber2, "
                        . "x_Address1 = :x_Address1, "
                        . "x_Date = :x_Date, "
                        . "x_Time = :x_Time, "
                        . "x_Status = :x_Status, "
                        . "x_M2 = :x_M2, "
                        . "x_M3 = :x_M3, "
                        . "x_Barcode = :Barcode, "
                        . "x_Price = :x_Price, "
                        . "x_Discount = :x_Discount, "
                        . "x_Number = :x_Number "
                        . "WHERE x_ID = :x_ID ";

                $stmt = $this->pdo->prepare($sql);

                $stmt->bindValue(':x_ID'          , $mStore_Order_DataClass->getx_ID()          );
                $stmt->bindValue(':x_Name'        , $mStore_Order_DataClass->getx_Name()        );
                $stmt->bindValue(':x_PhoneNumber1', $mStore_Order_DataClass->getx_PhoneNumber1());
                $stmt->bindValue(':x_PhoneNumber2', $mStore_Order_DataClass->getx_PhoneNumber2());
                $stmt->bindValue(':x_Address1'    , $mStore_Order_DataClass->getx_Address1()    );
                $stmt->bindValue(':x_Date'        , $mStore_Order_DataClass->getx_Date()        );
                $stmt->bindValue(':x_Time'        , $mStore_Order_DataClass->getx_Time()        );
                $stmt->bindValue(':x_Status'      , $mStore_Order_DataClass->getx_Status()      );
                $stmt->bindValue(':x_M2'          , $mStore_Order_DataClass->getx_M2()          );
                $stmt->bindValue(':x_M3'          , $mStore_Order_DataClass->getx_M3()          );
                $stmt->bindValue(':x_Barcode'     , $mStore_Order_DataClass->getx_Barcode()     );
                $stmt->bindValue(':x_Price'       , $mStore_Order_DataClass->getx_Price()       );
                $stmt->bindValue(':x_Discount'    , $mStore_Order_DataClass->getx_Discount()    );
                $stmt->bindValue(':x_Number'      , $mStore_Order_DataClass->getx_Number()      );

                $stmt->execute();

                $mrowCount = $stmt->rowCount();
                echo "\nA :\n{$mrowCount}\n";

                return TRUE;
            } 
            catch (\PDOException $e)            
            {
                return FALSE;
            }
        }

似乎没有匹配项，因此没有更新原因$mrowCount为0

我看到有一个匹配的 SQLITE数据库浏览器

我还将断点放在代码中，下面您可以从netbeans IDE的变量窗口中看到 $ sql ：

“ UPDATE命令SET x_Name =：x_Name，x_PhoneNumber1 =：x_PhoneNumber1， x_PhoneNumber2 =：x_PhoneNumber2，x_Address1 =：x_Address1，x_Date = ：x_Date，x_Time =：x_Time，x_Status =：x_Status，x_M2 =：x_M2，x_M3 = ：x_M3，x_Barcode =：条形码，x_Price =：x_Price，x_Discount = ：x_Discount，x_Number =：x_Number WHERE x_ID =：x_ID“

和：

因此您可以看到没有更新的情况下ID-2匹配

BTW， 没有错误，并返回TRUE

这是怎么回事？

Answer 1

我缩小了代码范围，最后发现如下问题：

x_Barcode =：条形码

必须如下：

x_Barcode =： x _ 条形码

这确实是一个无声的问题，因为没有错误，并且函数返回true

存在匹配项时，SQLITE3 PDO PHP的更新不起作用

1 个答案: