Question

所以我有一个问题，我无法解决，如果有人可以帮助我编写代码，我将很高兴。所以我正在使用INPUT和OUTPUT函数将字节转换为位，我的问题是我也找不到自动使用结果（输出）以二进制形式进行计算的方法。因此，如果我想将50 B转换为位，结果将得到400，而这400位（数字位）我也希望它们也像二进制一样显示。这是我的代码：

#include<iostream>
#include<conio.h>
using namespace std;

main()
{

int numB, numbit;   
int arr [100], i = 0,j;


//INPUT
cout<<"Please Enter the number of Bytes:";
cin>>numB;
cout<<"\n";

//Formula bytes into bits
numbit = numB * 8;

//OUTPUT
cout<<"Is equal to the number of bits:"<<numbit;
cout<<"\n";


    while (numbit>0) 
    {
        arr [i] = numbit%2;
        i++;
        numbit=numbit/2;
    }
    cout<<"Binary number is: ";
    for (j= i-1; j>=0; j--)
    {
        cout<< arr[j];

return 0;

system("Pause");
}
}

Answer 1

更新：BONUS-Round 现在都带有带符号和无符号数字（请注意，带符号的表示形式取决于实现，即编译器，字节序，操作系统，与无符号长度相同）< / p>

#include <iostream>
#include <bitset>
#include <cstdint>

int main()
{
    {
        unsigned unsigned_number{};
        std::cout << "Please Enter an unsigned:";

        std::cin >> unsigned_number;
        std::bitset<CHAR_BIT * sizeof(unsigned)> bits{unsigned_number};

        std::cout << "\nIs equal to the number of bits:" << bits << "\n";
    }
    {
        int32_t signed_number{};
        std::cout << "Please enter a signed:";

        std::cin >> signed_number;

        std::cout << "\nIs equal to the number of bits:";
        for (int i = 0; i < 4; ++i) {
            auto byte = reinterpret_cast<uint8_t*> (&signed_number) + i;
            std::bitset<8> bits{*byte};
            std::cout << bits;
        }
        std::cout << "\n";
    }
}

如何将我的输出用于另一个方程式？

1 个答案: