Question

我在bash中有一个程序来获取JSONline文件，每行有几百万个这样的对象（请参阅source）

{
  "company_number": "09626947",
  "data": {
    "address": {
      "address_line_1": "Troak Close",
      "country": "England",
      "locality": "Christchurch",
      "postal_code": "BH23 3SR",
      "premises": "9",
      "region": "Dorset"
    },
    "country_of_residence": "United Kingdom",
    "date_of_birth": {
      "month": 11,
      "year": 1979
    },
    "etag": "7123fb76e4ad7ee7542da210a368baa4c89d5a06",
    "kind": "individual-person-with-significant-control",
    "links": {
      "self": "/company/09626947/persons-with-significant-control/individual/FFeqke7T3LvGvX6xmuGqi5SJXAk"
    },
    "name": "Ms Angela Lynette Miller",
    "name_elements": {
      "forename": "Angela",
      "middle_name": "Lynette",
      "surname": "Miller",
      "title": "Ms"
    },
    "nationality": "British",
    "natures_of_control": [
      "significant-influence-or-control"
    ],
    "notified_on": "2016-06-06"
  }
}

我的JQ查询如下：

for file in psc_chunk_*; do
jq --slurp --raw-output 'def pad($n): range(0;$n) as $i | 
.[$i]; ([.[] | .data.natures_of_control | length] | max) as $mx |
.[] | 
select(.data) |
[.company_number, .data.kind, .data.address.address_line_1, .data.address.country, .data.address.locality, .data.address.postal_code, .data.address.premises, .data.identification.country_registered, .data.identification.legal_authority, .data.identification.legal_form, .data.identification.place_registered, .data.identification.registration_number, .data.ceased_on, .data.country_of_residence, "\(.data.date_of_birth.year)-\(.data.date_of_birth.month)", .data.etag, .data.links.self, .data.name, .data.name_elements.title, .data.name_elements.forename, .data.name_elements.middle_name, .data.name_elements.surname, .data.nationality, .data.notified_on, (.data.natures_of_control | pad($mx))] |
@csv' $file > $file.csv;
done

这可能会伤害到许多JQ专业人员的视线-提取key：value对效率不高，如果提供者碰巧更改了密钥名称，我的代码将无法使用。

有没有一种方法可以将所有json扁平化为csv 将键保留为标题 -额外的困难在于，列表natures_of_control存在变化条目数（为此我使用了pad函数来获取矩形结果）。

Answer 1

这是一种基于程序确定标头的方法。为了说明这一点，我们将注意力集中在单个对象上。

由于jq的paths内置函数会忽略指向null的路径，并且由于此处的要求之一就是不能忽略此类路径，因此我们首先定义一些类似于paths/0和{{1}的过滤器}：

paths/1

接下来，我们定义一个缩写长路径的函数。您可能希望根据自己的需求进行调整。

# Generate a stream of all paths, including paths to null
def allpaths:
  def conditional_recurse(f):  def r: ., (select(.!=null) | f | r); r;
  path(conditional_recurse(.[]?)) | select(length > 0);

def allpaths(filter):
  allpaths as $p | getpath($p) as $v | select($v | filter) | $p;

最后，我们通过生成一行标题，然后是一行相应的值，来将单个对象的情况汇总在一起：

# Input: an array denoting a path; output: a string
def abbreviate: if .[-1]|type == "number" then "\(.[-2]):\(.[-1])" else "\(.[-1])" end;

输出

对于问题中的JSON对象，由上面产生的输出（使用-r命令行选项）将为以下CSV：

[allpaths(scalars)] as $p
| ($p | map(abbreviate) | @csv),
  ([getpath($p[])] | @csv)

Answer 2

这是一种解决方案，可通过将输入JSON中的数组转换为“冒号分隔的值”来处理它们：

def atos: map(tostring) | join(":");

还使用了与该页面其他地方相同的通用allpaths过滤器：

# Generate a stream of all paths, including paths to null
def allpaths:
  def conditional_recurse(f):  def r: ., (select(.!=null) | f | r); r;
  path(conditional_recurse(.[]?)) | select(length > 0);

def allpaths(filter):
  allpaths as $p | getpath($p) as $v | select($v | filter) | $p;

再次针对单对象情况，可以按以下方式获得解决方案：

walk( if type == "array" then atos else . end )
| [allpaths(scalars)] as $p
| ($p | map(last) | @csv),
  ([getpath($p[])] | @csv)

输出

对于给定的输入，输出将是：

"company_number","address_line_1","country","locality","postal_code","premises","region","country_of_residence","month","year","etag","kind","self","name","forename","middle_name","surname","title","nationality","natures_of_control","notified_on"
"09626947","Troak Close","England","Christchurch","BH23 3SR","9","Dorset","United Kingdom",11,1979,"7123fb76e4ad7ee7542da210a368baa4c89d5a06","individual-person-with-significant-control","/company/09626947/persons-with-significant-control/individual/FFeqke7T3LvGvX6xmuGqi5SJXAk","Ms Angela Lynette Miller","Angela","Lynette","Miller","Ms","British","significant-influence-or-control","2016-06-06"

注意

此处介绍的解决方案仅适用于输入中的数组均为标量值的情况。

有效处理同构对象流

在下文中，从JSON对象内的键顺序无关紧要的意义上，假定对象流是同构的。

基础设施

allpaths和atos的基础架构如上所述，因此在此不再赘述。

辅助功能

# input: an object
def paths:
  walk( if type == "array" then atos else . end )
  | [allpaths(scalars)] ;

# input: an array of paths
def headers:
  map(last) | @csv ; 

# input: an object
def row($paths):
  walk( if type == "array" then atos else . end )
  | [getpath($paths[])]
  | @csv ;

处理输入流

以下代码使用input读取第一个对象，并使用inputs读取其余对象，因此使用-n命令行选项调用jq是必不可少的：

input as $first
| ($first|paths) as $paths
| ($paths | headers),
  ($first | row($paths)),
  (inputs | row($paths))

JSON-> csv创建标头行，如果发现空白字段，则填充标头

2 个答案:

输出

输出

注意

有效处理同构对象流

基础设施

辅助功能

处理输入流