Question

不确定这是哪里来的。我的目的是将ROUND（AVG（duration））除以lead_at和qualified_at（第二个子查询）的差异

SELECT (SELECT first_name 
        FROM users_permissions p WHERE p.user_id=a.assistant_id LIMIT 1) as Name, (SELECT u.lead_at, u.qualified_at FROM users u INNER JOIN aircalls ON u.id=aircalls.user_id WHERE u.qualified_at - u.lead_at) AS Difference, ROUND(AVG(duration)), count(id)
FROM aircalls a
WHERE assistant_id IS NOT NULL 
AND status='Call Connected' 
AND type='user' 
AND EXISTS (SELECT u.id FROM users u INNER JOIN aircalls ON u.id=aircalls.user_id AND u.status NOT IN (1,7))
AND EXISTS (SELECT p.user_id FROM users_permissions p INNER JOIN aircalls ON p.user_id=aircalls.user_id AND p.is_agent NOT IN (1))
AND year(a.created_at)=2019
GROUP BY(SELECT first_name 
         FROM users_permissions p WHERE p.user_id=a.assistant_id LIMIT 1)

Answer 1

问题在您的第二选择（差异）中，而不是推论两个值，您只是将它们都用逗号分隔。另外，where中的select子句没有有效值。

是：

SELECT u.lead_at, u.qualified_at FROM users u INNER JOIN aircalls ON u.id=aircalls.user_id WHERE u.qualified_at - u.lead_at) AS Difference

这是该错误行的更正：

(SELECT u.lead_at - u.qualified_at FROM users u INNER JOIN aircalls ON u.id=aircalls.user_id) AS Difference

操作数应在我的SQL查询中包含1列错误

1 个答案: